Chapter 11: Problem 101
If \(y=m x+4\) is a tangent to both the parabolas, \(y^{2}=4 x\) and \(x^{2}=2 b y\), then \(b\) is equal to: (a) \(-32\) (b) \(-64\) (c) \(-128\) (d) 128
Short Answer
Expert verified
The value of \( b \) is \(-128\).
Step by step solution
01
Understand the relationships
First, recall that the line \( y = mx + c \) is tangent to a parabola when the quadratic equation formed by substitution has a discriminant of zero.
02
Substitute in the first parabola
The given line is \( y = mx + 4 \). Substitute this equation into the first parabola \( y^2 = 4x \).\[ (mx + 4)^2 = 4x \] Simplify to form a quadratic in terms of \( x \).\[ (mx + 4)^2 = 4x \Rightarrow m^2x^2 + 8mx + 16 = 4x \]\[ m^2x^2 + (8m - 4)x + 16 = 0 \] The discriminant \( b^2 - 4ac \) should be zero: \[ (8m-4)^2 - 4(m^2)(16) = 0 \].
03
Calculate the discriminant for the first parabola
Solve the equation \[ (8m-4)^2 - 64m^2 = 0 \]. Simplify and solve to find \( m \).\[ (8m-4)^2 = 64m^2 \] \[ 64m^2 - 64m + 16 = 64m^2 \] \[ -64m + 16 = 0 \] \[ m = \frac{1}{4} \].
04
Substitute in the second parabola
Now, substitute \( y = mx + 4 \) into the second parabola \( x^2 = 2by \).\[ x^2 = 2b(mx + 4) \]\[ x^2 = 2b(mx) + 8b \] Rearrange and form a quadratic equation in terms of \( y \): \[ x^2 - 2bmx - 8b = 0 \]. The discriminant again should be zero.
05
Condition for tangency for the second parabola
Apply the condition of tangency \( b^2 - 4ac = 0 \) to this quadratic equation: \[ (2bm)^2 - 4(1)(-8b) = 0 \]. Use \( m = \frac{1}{4} \) in the equation and solve for \( b \).\[ (2b \times \frac{1}{4})^2 + 32b = 0 \] \[ \frac{b^2}{4} + 32b = 0 \] \[ b^2 + 128b = 0 \].
06
Solve for b
Factor out \( b \) from the equation: \[ b(b + 128) = 0 \]. So, either \( b = 0 \) or \( b = -128 \). Since \( b eq 0 \) (as the parabola equation \( x^2 = 2by \) would not make sense), the value is \( b = -128 \).
07
Verify the choice
From the potential choices, verify that \( b = -128 \) is consistent with the answer choices provided in the question. Thus \( b = -128 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Line
A tangent line is a straight line that touches a curve at exactly one point. This unique feature means that at the point of contact, both the tangent line and the curve have the same slope. For parabolas, which are U-shaped curves, a tangent is a line that meets the parabola at just one point, not crossing it.
In mathematical terms, if a line is given by the equation \( y = mx + c \), it will be tangent to a parabola if, when substituted into the parabola's equation, the resulting quadratic equation has its discriminant equal to zero. The discriminant is a measure that helps us understand the nature of the roots of the quadratic equation.
In mathematical terms, if a line is given by the equation \( y = mx + c \), it will be tangent to a parabola if, when substituted into the parabola's equation, the resulting quadratic equation has its discriminant equal to zero. The discriminant is a measure that helps us understand the nature of the roots of the quadratic equation.
- If the discriminant is zero, the quadratic equation has exactly one solution, meaning the line just touches the parabola without crossing it.
- A positive discriminant indicates two points of intersection (the line crosses the parabola), while a negative discriminant implies no intersection.
Discriminant
The discriminant is an essential part of the quadratic formula. It determines the nature and number of solutions of a quadratic equation. When dealing with quadratic equations in the standard form \( ax^2 + bx + c = 0 \), the discriminant \( \Delta \) is given by the formula \( \Delta = b^2 - 4ac \).
This small but powerful value tells us:
This small but powerful value tells us:
- If \( \Delta > 0 \), we get two distinct real solutions.
- If \( \Delta = 0 \), we have exactly one real solution, indicating the line is tangent to the parabola at one point.
- If \( \Delta < 0 \), there are no real solutions, and the line does not intersect the parabola.
Quadratic Equation
A quadratic equation is a polynomial equation of degree two. It follows the general form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). These equations are vital in mathematics because they frequently describe various natural phenomena and geometric shapes, such as parabolas.
To solve a quadratic equation, we often use methods such as factoring, completing the square, or the quadratic formula. The quadratic formula being:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\]This formula not only provides the solutions for \( x \) but also incorporates the discriminant, \( b^2 - 4ac \), which indicates the type of solutions we should expect.
To solve a quadratic equation, we often use methods such as factoring, completing the square, or the quadratic formula. The quadratic formula being:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\]This formula not only provides the solutions for \( x \) but also incorporates the discriminant, \( b^2 - 4ac \), which indicates the type of solutions we should expect.
- Two distinct solutions if the discriminant is positive.
- One solution if it's zero, suggesting a tangent case.
- No real solutions if negative.