Chapter 10: Problem 81
The point of intersection of the lines \(\left(a^{3}+3\right) x+a y+a-3=0\) and \(\left(a^{5}+2\right) x+(a+2) y+2 a+3=0\) (a real) lies on the \(y\)-axis for |Online May 7, 2012] (a) no value of \(a\) (b) more than two values of \(a\) (c) exactly one value of \(a\) (d) exactly two values of \(a\)
Short Answer
Step by step solution
Identify Intersection Conditions
Eliminate x From Equations
Solve for y in Both Equations
Equate the Two y-values
Cross-Multiply and Rearrange
Solve Quadratic Equation
Assess the Number of Solutions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coordinate Geometry
To find a point of intersection, you typically solve the equations of the two lines simultaneously, meaning you find a common solution for both equations. For lines in two-dimensional space, their equations are often linear, represented in the form \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept.
- Lines intersect at a single point if they are not parallel.
- If they are the same line, there are infinitely many points of intersection.
- If they are parallel, they do not intersect.
Quadratic Equations
In the exercise, to solve for the parameter \(a\) where the intersection lies on the y-axis, a quadratic equation emerges, \(a^2 + 8a + 6 = 0\). Solving this equation employs the quadratic formula:
- The quadratic formula is \(a = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
- It delivers possible values for \(a\) based on any potential intersection.
System of Linear Equations
In this exercise, the intersection of two lines is investigated by creating a system of equations that need to be solved simultaneously.
- Each line in the problem is represented by a linear equation.
- The solution, or intersection point, must satisfy both equations regarding how they relate to x and y on the coordinate plane.
- Setting the x-coordinate to zero helps resolve where the point lies solely on the y-axis.