Chapter 10: Problem 1
A triangle \(A B C\) lying in the first quadrant has two vertices as \(A(1,2)\) and \(B(3,1)\). If \(\angle B A C=90^{\circ}\), andar \((\triangle A B C)=5 \sqrt{5}\) sq. units, then the abscissa of the vertex \(C\) is: (a) \(1+\sqrt{5}\) (b) \(1+2 \sqrt{5}\) (c) \(2+\sqrt{5}\) (d) \(2 \sqrt{5}-1\)
Short Answer
Step by step solution
Understand the Problem
Use Right Angle Property
Calculate Slope of Line AB
Find Slope of Line AC
Utilize Area Formula
Determine Coordinates of Point C
Solve for x
Final Step: Verify the Answer
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Key Concepts
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