/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Crude oil is being transferred f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Crude oil is being transferred from a full rectangular storage container with dimensions 4 meters by 9 meters by 10 meters into a cylindrical transportation container that has a diameter of 6 meters. What is the minimum possible length for a transportation container that will hold all of the oil? $$ \begin{array}{l}{\text { (A) } 40 \pi} \\ {\text { (B) } \frac{40}{\pi}} \\\ {\text { (C) } 60 \pi} \\ {\text { (D) } \frac{120}{\pi}}\end{array} $$

Short Answer

Expert verified
\( \frac{40}{\text{pi}} \)

Step by step solution

01

Calculate the Volume of the Rectangular Container

To begin, calculate the volume of the rectangular storage container using the formula for the volume of a rectangular prism: \[ V_{\text{rect}} = \text{length} \times \text{width} \times \text{height} \]Substitute the given dimensions: \[ V_{\text{rect}} = 4 \times 9 \times 10 = 360 \text{ cubic meters} \]
02

Calculate the Volume of the Cylindrical Container

Next, calculate the volume of the cylindrical transportation container using the formula for the volume of a cylinder: \[ V_{\text{cyl}} = \frac{\text{diameter}}{2} \times \frac{\text{diameter}}{2} \times \text{height} \times \text{pi} \]Given the diameter, the radius is: \[ r = \frac{6}{2} = 3 \text{ meters} \]The volume of the cylinder becomes: \[ V_{\text{cyl}} = \text{pi} \times 3^2 \times \text{height} = 9\text{pi} \times \text{height} \]
03

Equate the Volumes to Find the Minimum Height

To ensure that the cylindrical container can hold all the oil from the rectangular container, set their volumes equal:\[ 360 = 9\text{pi} \times \text{height} \]Solving for height: \[ \text{height} = \frac{360}{9\text{pi}} = \frac{40}{\text{pi}} \]
04

Verify the Answer

Finally, verify if the obtained height corresponds to one of the given choices. The correct answer is choice (B): \[ \text{height} = \frac{40}{\text{pi}} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rectangular prism volume
A rectangular prism is a solid figure that has six faces, all of which are rectangles. Calculating the volume of a rectangular prism is straightforward. The volume \( V \) is found by multiplying the length, width, and height of the prism. This can be written as: \[ V_{\text{rect}} = \text{length} \times \text{width} \times \text{height} \]
Let's look at an example. In the problem, the rectangular storage container has dimensions of 4 meters (length), 9 meters (width), and 10 meters (height). By substituting these values into the volume formula, we get: \[ V_{\text{rect}} = 4 \times 9 \times 10 = 360 \text{ cubic meters} \]
So, the volume of this rectangular container is 360 cubic meters. This means it can hold 360 cubic meters of crude oil.
The formula is easy to remember and apply, as it simply involves multiplying three numbers together.
cylindrical volume
A cylinder is a 3D shape with two parallel circles of the same size at the top and bottom, and a curved surface connecting them. To find the volume of a cylinder, you need to know its radius and height. The formula for the volume of a cylinder is: \[ V_{\text{cyl}} = \text{pi} \times r^2 \times h \]
Where \( \text{pi} \) (approximately 3.14159) is a constant, \( r \) is the radius, and \( h \) is the height.
In the given problem, the diameter of the cylindrical transportation container is 6 meters. The radius is half of the diameter, so: \[ r = \frac{6}{2} = 3 \text{ meters} \]
In order to hold all the oil from the rectangular container, the volume of the cylindrical container needs to be equal to the volume of the rectangular container. Therefore: \[ V_{\text{cyl}} = \text{pi} \times 3^2 \times h = 9\text{pi} \times h \]
We already know that the volume of the rectangular container is 360 cubic meters, so we set the equations equal: \[ 360 = 9\text{pi} \times h \]
Solving for \( h \), we divide both sides by \( 9\text{pi} \): \[ h = \frac{360}{9\text{pi}} = \frac{40}{\text{pi}} \]
This calculation gives us the minimum height \( h \) for the cylindrical container to hold the entire volume of oil, making the answer \( \frac{40}{\text{pi}} \).
geometry problem solving
Solving geometry problems often involves calculating volumes and other measurements to determine how different shapes interact. Here are key steps to solve problems, such as transferring volumes between containers:
  • Identify the Shapes: Recognize the shapes involved—in this case, a rectangular prism and a cylinder.
  • Use the Relevant Formulas: Apply the correct volume formulas for each shape.
  • Substitute the Given Measurements: Carefully input the dimensions provided in the problem.
  • Set Up Equations: If transferring between containers, set their volumes equal to find any unknown variables.
  • Solve for Unknowns: Perform algebraic manipulations to solve for the required variable.
In our example, starting by determining the volume of the rectangular prism and the formula for the volume of the cylindrical container allowed us to set their volumes equal. Then, solving for the unknown height provided us with the solution. Understanding how to apply these steps can simplify many geometry-related exercises and real-life scenarios.
These methods are crucial tools for tackling a variety of geometry problems, ensuring that you can find solutions efficiently and accurately.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Carbon makes up what percent of the mass of one mole of chloroform? Round your answer to the nearest whole percent and ignore the percent sign when entering your answer.

A microbiologist is studying the effects of a new antibiotic on a culture of \(20,000\) bacteria. When the antibiotic is added to the culture, the number of bacteria is reduced by half every hour. What kind of function best models the number of bacteria remaining in the culture after the antibiotic is added? $$\begin{array}{l}{\text { (A) A linear function }} \\ {\text { (B) A quadratic function }} \\ {\text { (C) A polynomial function }} \\ {\text { (D) An exponential function }}\end{array}$$

What value of \(x\) satisfies the equation $$\frac{2}{3}(5 x+7)=8 x?$$

$$ b=\frac{L}{4 \pi d^{2}} $$ The brightness of a celestial body, like a star, decreases as you move away from it. In contrast, the luminosity of a celestial body is a constant number that represents its intrinsic brightness. The inverse square law, shown above, is used to find the brightness, \(b,\) of a celestial body when you know its luminosity, \(L,\) and the distance, \(d\) , in meters to the body. Which equation shows the distance to a celestial body, given its brightness and luminosity? $$ \begin{array}{l}{\text { (A) } d=\frac{1}{2} \sqrt{\frac{L}{\pi b}}} \\\ {\text { (B) } d=\sqrt{\frac{L}{2 \pi b}}} \\ {\text { (C) } d=\frac{\sqrt{L}}{2 \pi b}} \\ {\text { (D) } d=\frac{L}{2 \sqrt{\pi b}}}\end{array} $$

If \(\frac{1}{4} x=5-\frac{1}{2} y,\) what is the value of \(x+2 y ?\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.