/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Traveling at an average speed of... [FREE SOLUTION] | 91影视

91影视

Traveling at an average speed of 58 miles per hour, Terence drives 145 miles. Three hours later, Terence makes the return trip at the same speed. How much total time elapses between Terence's original departure and final return? A. 2.5 hours B. 5 hours C. 5.5 hours D. 8 hours

Short Answer

Expert verified
The total time elapsed between Terence's original departure and final return is 8 hours. Answer: \(\boxed{\text{D. 8 hours}}\).

Step by step solution

01

1. Find the time it takes to travel 145 miles at 58 mph

To find the time it takes for Terence to travel 145 miles at 58 mph, we can use the distance formula: distance = speed 脳 time 145 miles = 58 mph 脳 t Now, we need to solve for t: t = 145 miles / 58 mph
02

2. Calculate t

Now we can calculate t by dividing 145 by 58: t = 145/58 = 2.5 hours So, it takes Terence 2.5 hours to travel 145 miles at an average speed of 58 mph.
03

3. Calculate time for the return trip

Since the return trip is at the same speed, it will also take Terence 2.5 hours to travel back.
04

4. Add time for the stop

Terence stops for 3 hours before making the return trip. So, we need to add those 3 hours to the total time elapsed.
05

5.Calculate total time elapsed

Now, we can calculate the total time elapsed by adding the times for each leg of the trip and the time for Terence's stop: Total time elapsed = 2.5 hours (original trip) + 3 hours (stop) + 2.5 hours (return trip) Total time elapsed = 8 hours So, the total time elapsed between Terence's original departure and final return is 8 hours. The correct answer is D. 8 hours.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance Speed Time Problems
Understanding distance, speed, and time relationships is a fundamental concept in mathematics, especially when it comes to preparing for exams like the GED. The basic formula connecting these three quantities is expressed as:

\[ \text{Distance} = \text{Speed} \times \text{Time} \]

This equation can be rearranged to solve for any one of the three variables, given the other two. Let's say you're given the speed and distance, like in Terence's problem, you can find the time by rearranging the formula to \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \).

Considerations for Distance Speed Time Calculations

  • Units: Ensure that the units for speed and time are compatible. If speed is in miles per hour and distance in miles, time must be calculated in hours.
  • Consistent Speed: The formula assumes a constant speed throughout the journey. Any changes in speed would require additional calculations.
  • Multiple Legs: When a trip has several parts, calculate each part separately and sum them for the total time. In the GED math practice scenario with Terence, the trip had two legs plus a stop.
Remember that knowing how to manipulate this formula is crucial for solving distance, speed, and time problems effectively.
GED Algebra Problems
Algebra is a significant component of the GED math test, and it requires students to be comfortable with using letters to represent numbers in equations and inequalities. One common type of problem involves solving for an unknown, which can be approached using algebraic manipulation.

For example, when determining the time it takes for Terence to travel a certain distance, we start with the algebraic expression \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \). Solving this provides us with a specific value for the time variable. This step is critical in GED algebra problems as it demonstrates the ability to manipulate and solve equations.

Key Algebra Concepts

  • Variables: Variables represent unknown values and are central to algebraic equations.
  • Solving Equations: The process of finding the value of the variable that makes the equation true.
  • Equation Balancing: Whatever operation is done to one side of the equation should be done to the other to maintain balance.
Strengthening these algebra skills is crucial for success in GED math and beyond.
GED Test Preparation
Proper preparation for the GED test is essential to succeed, and for the math section, this involves a solid understanding of a range of mathematical concepts, including algebra, geometry, data analysis, and arithmetic operations.

When preparing for the math section, practice a variety of problems to become comfortable with different types of questions. Use practice tests to identify areas of strength and weakness. Focus on improving weak areas while also reinforcing stronger skills.

Effective Study Strategies for the GED Math Test

  • Understand the Concepts: Don鈥檛 just memorize procedures; aim to understand the underlying concepts.
  • Practice Regularly: Consistency in practice helps to reinforce learning and improve retention.
  • Simulate Testing Conditions: Taking timed practice tests can help you manage time during the actual exam.
Remember, resourcefulness is as important as memory and practice. Familiarize yourself with the types of math tools allowed, such as calculators, and how to use them effectively during the test.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The diagram above shows various layers of rock that have been deposited over time. Drag and drop the rock layers into the appropriate boxes. (For this practice test, write the letters in the boxes.) The oldest rock layer: The newest rock layer: (a) rock layer #1 (b) rock layer #2 (c) rock layer #3 (d) rock layer #4

How does the 鈥淔uel-Saving Habits鈥 section (paragraph 6) of the Department of Energy article relate to the 鈥淔uel-Saving Technology Highlight鈥 section (paragraph 7)? A. The 鈥淔uel-Saving Habits鈥 section lists changes drivers can make to save fuel, while the 鈥淔uel-Saving Technology Highlight鈥 contradicts this list by claiming there is no need to drive differently. B. The 鈥淔uel-Saving Habits鈥 list begins by cautioning against a bad driving habit; the 鈥淔uel-Saving Technology Highlight鈥 builds on this advice by recommending a device that automatically reduces this habit. C. The 鈥淔uel-Saving Habits鈥 section implies that there are several ways to reduce fuel consumption, while the 鈥淔uel-Saving Technology Highlight鈥 implies that one of these ways is more effective than the others. D. The 鈥淔uel-Saving Habits鈥 section focuses only on ways to operate a vehicle while the 鈥淔uel-Saving Technology Highlight鈥 focuses on devices that can be installed in vehicles.

Which of the following correctly represents the ratio of Comedy to Other Types, as given in the bar graph? A. 5:2 B. \(25: 12\) C. \(2: 5\) D. \(12: 25\)

If the equation of a line is \(y=\frac{1}{2} x+3\), then mark on the graph the point where the line crosses the \(y\)-axis and the point where the line crosses the \(x\)-axis.

An airplane can hold 325 passengers, 30 in first class and the rest in coach. If a first-class ticket costs \(700 and a coach ticket costs \)250, then what is the minimum revenue that the airplane will gross on a flight in which exactly 3 seats remain empty?

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.