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What region of the light spectrum corresponds to the characteristic emissions in the Balmer series? A. UV B. Visible C. Infrared D. X-ray

Short Answer

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B. Visible

Step by step solution

01

- Understand the Balmer Series

The Balmer series describes the spectral line emissions of the hydrogen atom when an electron transitions from a higher energy level (n > 2) to the energy level n = 2.
02

- Identify the Region

The emissions of the Balmer series are known to fall within a specific part of the electromagnetic spectrum.
03

- Recognize Emission Region

The Balmer series emissions fall within the visible light spectrum. This is why transitions ending at n = 2 produce visible lines that can be seen with the naked eye.
04

- Choose the Correct Option

Among the given options: A. UV, B. Visible, C. Infrared, D. X-ray, the visible spectrum is the correct region for the Balmer series emissions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Spectrum
The electromagnetic spectrum is the range of all types of electromagnetic radiation. Radiation is energy that travels and spreads out as it moves. Visible light that we see is one type of electromagnetic radiation. Other types include radio waves, microwaves, infrared light, ultraviolet light, X-rays, and gamma rays.

  • Radio waves have the longest wavelengths and the least energy.
  • Gamma rays have the shortest wavelengths and the most energy.
Each type of radiation is characterized by its wavelength or frequency. Frequency is the number of wave cycles that pass a given point per unit time. Long wavelengths have low frequencies, while short wavelengths have high frequencies.

The visible spectrum is the part of the electromagnetic spectrum that can be seen by the human eye. It ranges from roughly 400 to 700 nanometers (nm). Light in this range appears as different colors, from violet at the low end to red at the high end.

Understanding the electromagnetic spectrum helps us know where different kinds of light fall, which is crucial when studying phenomena like the Balmer series.
Hydrogen Atom Emission
When an electron in a hydrogen atom moves from a higher energy level (higher orbit) to a lower energy level (lower orbit), it emits energy. This energy is released in the form of light, known as emission.

The hydrogen atom's emission spectrum shows discrete lines rather than a continuous spectrum. This occurs because electrons can only occupy specific energy levels in an atom.

Let's break down how this works:
  • Each energy level (or orbit) is quantized, meaning only specific orbits are allowed.
  • When an electron falls from a higher to a lower orbit, it releases a photon, which is a packet of light energy.
  • The wavelength of the emitted light corresponds to the energy difference between the two orbits.
The Balmer series specifically refers to emissions where the electron falls to the n=2 level from any level higher than n=2 (n > 2). These emissions are particularly significant because they fall within the visible light spectrum. By studying these spectral lines, scientists can understand more about the properties and behaviors of atoms.
Visible Light Spectrum
The visible light spectrum is a small part of the electromagnetic spectrum that can be seen by the human eye. It is typically described as ranging from 400 to 700 nanometers (nm) in wavelength.

Here is the breakdown of the colors in the visible spectrum from shortest to longest wavelength:
  • Violet (around 400 nm)
  • Blue
  • Green
  • Yellow
  • Orange
  • Red (around 700 nm)
The Balmer series lies within this range, which is why we see these emissions as visible light. Different lines in the Balmer series correspond to different colors; for instance, the most well-known line is H-alpha, which is in the red part of the spectrum at about 656 nm.

Understanding the visible light spectrum is important because it explains why we can see the Balmer series emissions with our naked eyes. This also allows astronomers to use these visible spectral lines to study distant stars and galaxies. Knowing the precise wavelengths and transitions in the Balmer series aids in identifying the presence of hydrogen and understanding the composition of astronomical objects.

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Most popular questions from this chapter

If an electron is promoted from \(n=2\) to \(n=5\), as Balmer observed, which of the following possibilities BEST describes the source of the line spectra observed? A. A photon is absorbed. B. A photon is emitted. C. An electron is absorbed. D. An electron is emitted.

Suppose a scientist tried to obtain a Balmer series with a sample of deuterium. How would this sample change the appearance of the emissions in the line spectrum? A. Fewer emission lines B. More emission lines C. Same number of emission lines with split peaks D. Same number of emission lines without split peaks (that is, no change in appearance)

What is the proper electron configuration of hydrogen in its elemental state? A. \(1 \mathrm{~s}^0\) B. \(1 s^1\) C. \(1 \mathrm{~s}^2\) D. None of the above

Due to changes in climate and poor management of ion content in the water, the swimming pool has now become supersaturated with calcium sulfate. What combination of events could have caused this to occur? A. Cooling of the pool followed by addition of calcium sulfate B. Warming of the pool followed by addition of calcium sulfate C. Addition of calcium sulfate followed by cooling of the pool and then subsequent warming of the pool D. Warming of the pool followed by addition of calcium sulfate and then cooling of the pool

What is the net overall equation for the cell? A. \(\mathrm{LiCoO}_2+6 \mathrm{C} \leftrightharpoons \mathrm{Li}_x \mathrm{C}_6+\mathrm{Li}_{1-x} \mathrm{CoO}_2\) B. \(\mathrm{LiCoO}_2+x \mathrm{Li}^{+}+6 \mathrm{C} \leftrightharpoons \mathrm{Li}_x \mathrm{C}_6+\mathrm{Li}_{1-x} \mathrm{CoO}_2\) C. \(\mathrm{Li}^{+}+6 \mathrm{C} \leftrightharpoons \mathrm{Li}_x \mathrm{C}_6\) D. \(\mathrm{LiCoO}_2+x \mathrm{Li}^{+} \leftrightharpoons \mathrm{Li}_{1-x} \mathrm{CoO}_2\)

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