Chapter 18: Problem 766
There are two boxes. Box I contains 4 Red and 3 white balls. Box II contains 5 red and 2 white balls. Two balls are transferred from Box I to Box II. One ball is then drawn from box II randomly. What is the probability for that ball to be red? (a) \((43 / 63)\) (b) \((23 / 73)\) (c) \((34 / 63)\) (d) None
Short Answer
Step by step solution
Define the Events
Calculate Probabilities of Events A1, A2, and A3
Calculate P(B|A1), P(B|A2), and P(B|A3)
Use Conditional Probability Formula to Calculate P(B)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conditional Probability
Combinatorics
- Choosing 2 red balls (Event A1): Utilized \( \binom{4}{2} \).
- Choosing 1 red and 1 white ball (Event A2): Utilized \( \binom{4}{1} \binom{3}{1} \).
- Choosing 2 white balls (Event A3): Utilized \( \binom{3}{2} \).
Event Calculation
- Event A1: Presentation of both balls being red leads to a new configuration in the second box.
- Event A2: Presentation of one red and one white ball alters proportions differently in the second box.
- Event A3: Presentation of both white balls modifies yet another distinct setup.