Chapter 13: Problem 1187
The solution of the differential equation \((\mathrm{dy} / \mathrm{dx})=(\mathrm{y} / \mathrm{x})+\left[\\{\Phi(\mathrm{y} / \mathrm{x})\\} /\left\\{\Phi^{1}(\mathrm{y} / \mathrm{x})\right\\}\right]\) is: (A) \(\phi(\mathrm{y} / \mathrm{x})=\mathrm{kx}\) (B) \(\Phi(\mathrm{y} / \mathrm{x})=\mathrm{ky}\) (C) \(\mathrm{x} \cdot \Phi(\mathrm{y} / \mathrm{x})=\mathrm{k}\) (D) \(\mathrm{y} \cdot \Phi(\mathrm{y} / \mathrm{x})=\mathrm{k}\)
Short Answer
Step by step solution
Rewrite the differential equation
Separate variables
Integrate both sides
Rewrite in terms of y and x and compare to the given choices
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Separation of Variables
For example, if you encounter an equation like \( \frac{dy}{dx} - \frac{y}{x} = \frac{\Phi(\frac{y}{x})}{\Phi'(\frac{y}{x})} \), our goal is to express it so that each side depends on only one variable.
One way to do this is by substitution. In our example, we substitute \( v = \frac{y}{x} \), which allows us to express \( y \) as \( y = xv \). We can then separate variables in terms of \( v \) and \( x \), simplifying our differential equation and making it more straightforward to handle.
**Key points:**
- Use substitution to express one variable in terms of another.
- Rearrange the equation to isolate variables on opposite sides.
- This simplification often leads to an equation that is easier to integrate.
Integration Techniques
When you have an equation like \( \int x \frac{dv}{dx} dx = \int \frac{\Phi(v)}{\Phi'(v)} dv \), integrating both sides can help us derive a relationship between the variables of interest.
Here are a few basic integration techniques:
- **Direct Integration:** If the function is one we know, we can apply the rule directly. For instance, \( \int x \, dx = \frac{x^2}{2} + C \).
- **Substitution:** Sometimes changing variables can simplify the integration process. As shown, letting \( v = \frac{y}{x} \) helped separate variables.
- **Parts:** Although not used directly here, integration by parts is valuable for functions that are products of two simpler functions.
Derivative
In our example, the derivative \( \Phi'(\frac{y}{x}) \) stands for the rate of change of the function \( \Phi \) with respect to \( \frac{y}{x} \). Differentials like \( \frac{dy}{dx} \) alert us to changes in \( y \) relative to changes in \( x \).
Calculating derivatives enables us to model the dynamic nature of processes over time. In this solution, after substituting \( v = \frac{y}{x} \), differentiating \( y = xv \) with respect to \( x \) gives us \( \frac{dy}{dx} = x \frac{dv}{dx} + v \), showcasing a direct application of the derivative to rearrange and solve the differential equation.
**Important notes:**
- Derivatives reflect instantaneous rates of change.
- They help make predictions about complex, changing systems.
- Mastering derivatives enables deeper insights into the behavior of functions.
Constant of Integration
In the equation \( xv = \int \frac{\Phi(v)}{\Phi'(v)} dv + C \), our resulting expression includes \( C \) to encompass all possible solutions that could satisfy the initial differential equation.
Here’s why it’s important:
- **General Solutions:** Without \( C \), you only have a specific solution rather than the general solution needed for most differential equations.
- **Flexibility in Solutions:** Different contexts might require adjusting \( C \) to meet boundary or initial conditions.
- **Continuous Representation:** \( C \) ensures that our solutions form a continuous spectrum, allowing for further exploration of function behavior.