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The dissociation constant of acetic acid at a given temperature is \(1.69 \times 10^{-5} .\) The degree of dissociation of \(0.01 \mathrm{M}\) acetic acid in the presence of \(0.01 \mathrm{M} \mathrm{HCl}\) is equal to (1) \(0.41\) (2) \(0.13\) (3) \(1.69 \times 10^{-3}\) (4) \(0.013\). (5) \(0.04\)

Short Answer

Expert verified
1.69 \times 10^{-3}

Step by step solution

01

Write the dissociation equation

The dissociation equation for acetic acid (\text{CH}_3\text{COOH}) in water is:\[\text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+\]
02

Define the dissociation constant

The dissociation constant (\text{K}_a) is given as:\[\text{K}_a = 1.69 \times 10^{-5}\]
03

Write the expression for \text{K}_a

For acetic acid, the dissociation constant expression is:\[\text{K}_a = \frac{[\text{CH}_3\text{COO}^-][\text{H}^+]}{[\text{CH}_3\text{COOH}]}\]
04

Include the initial concentration and variables

Given initial concentrations:\[[\text{CH}_3\text{COOH}]_0 = 0.01 \text{ M}, [\text{HCl}] = 0.01 \text{ M}\]Define degree of dissociation as \( \text{α} \).
05

Assume \text{H}^+ concentration from HCl

\text{HCl} is a strong acid and will fully dissociate, giving:\[[\text{H}^+] = 0.01 \text{ M} + 0.01 \text{α} \text{ (from acetic acid)}\]Since \text{α} is expected to be small, approximate it as:\[[\text{H}^+] ≈ 0.01 \text{ M}\]
06

Substitute values back into \text{K}_a equation

Substitute the known values:\[\text{K}_a = 1.69 \times 10^{-5} = \frac{(0.01 \text{α})(0.01)}{0.01 (1- \text{α})}\]Since \text{α} is very small, \(1- \text{α} \approx 1\):\[1.69 \times 10^{-5} = 0.01 \text{α}\]
07

Solve for \text{α}

Rearrange to solve for \text{α}:\[ \text{α} = \frac{1.69 \times 10^{-5}}{0.01} = 1.69 \times 10^{-3}\]
08

Compare to given options

Compare the calculated \text{α} to the provided options:Option (3) is: \(1.69 \times 10^{-3}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

dissociation equation
In chemistry, the dissociation equation represents the splitting of a compound into its constituent ions when dissolved in water. For acetic acid (\text{CH}_3\text{COOH}), it dissociates as follows:

\(\text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \)

This equation shows that acetic acid partially breaks down into acetate ions (\(\text{CH}_3\text{COO}^- \)) and hydrogen ions (\(\text{H}^+ \)) in an aqueous solution. The nature of acetic acid as a weak acid means it does not fully dissociate. Understanding this equation is crucial as it lays the foundation for calculating the degree of dissociation and further using it to find the dissociation constant expression.
acetic acid
Acetic acid, also known as ethanoic acid, is a common weak acid with the chemical formula \(\text{CH}_3\text{COOH} \). Found in vinegar, it has a distinctive sour taste and pungent smell. Unlike strong acids, which dissociate completely in water, acetic acid only partially dissociates. This attribute makes it essential to apply specific calculations, such as those involving the dissociation constant (\(\text{K}_a \)), when working with it.

For students, it's vital to differentiate between strong acids like hydrochloric acid (\(\text{HCl}\)), which dissociate entirely, and weak acids like acetic acid.
degree of dissociation
The degree of dissociation (\text{α}) is a measure of how much a weak acid dissociates in solution. It is defined as the ratio of the concentration of dissociated acid to the initial concentration of the acid.

In the context of acetic acid, if we start with an initial concentration of \(\text{CH}_3\text{COOH} \) (denoted as \([\text{CH}_3\text{COOH}]_0 = 0.01 \text{ M}\)), and part of it dissociates into ions, the degree of dissociation is calculated by:
\text{α} = \(\frac{[\text{CH}_3\text{COO}^-]}{[\text{CH}_3\text{COOH}]_0} \).

In the given problem, \(\text{α} \) was found by relating the dissociation constant to the concentrations involved and solving for \(\text{α} \). This led to the value of \(\text{α} = 1.69 \times 10^{-3} \).
dissociation constant expression
The dissociation constant (\text{K}_a) of an acid quantifies its strength in terms of its ability to donate protons to water, creating ions. For acetic acid, the expression is formulated as:

\(\text{K}_a = \frac{[\text{CH}_3\text{COO}^-][\text{H}^+]}{[\text{CH}_3\text{COOH}]}\)

This equation represents the equilibrium constant of the dissociation reaction. By substituting the known concentrations into this expression, students can calculate key parameters like the degree of dissociation or pH of the solution.
initial concentration
The initial concentration of acetic acid is crucial in determining the degree of dissociation and calculating the dissociation constant. In the problem, we start with an initial concentration of \(\text{CH}_3\text{COOH} = 0.01 M\) and consider the presence of \(\text{HCl} = 0.01 M\) as well.

This initial concentration helps set up the initial conditions before dissociation occurs and is crucial for setting up the equation to solve for the degree of dissociation. When \(\text{HCl}\) is added, it fully dissociates and alters the \(\text{H}^+\) ion concentration in the solution, which, in turn, affects the acid dissociation equilibrium calculations.

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