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What is the probability of drawing the letters \(G\), then \(M\), then \(A\) and finally, \(T\) (in the order it spells GMAT \(^{\oplus}\) ) from a set of alphabetical cards (one card for each letter of the alphabet) if each card is replaced before the next card is drawn? A. \(1 / 26\) B. \(1 / 104^4\) C. \(1 / 676\) D. \(1 / 676^4\) E. \(1 / 26^4\)

Short Answer

Expert verified
E. \( \frac{1}{26^4} \)

Step by step solution

01

Identify total possible outcomes per draw

There are 26 letters in the alphabet, so each draw from the set of alphabetical cards has 26 possible outcomes.
02

Determine the probability of drawing the first letter (G)

Since there are 26 letters, and G is one of them, the probability of drawing G is \(\frac{1}{26}\).
03

Determine the probability of drawing the second letter (M)

Each card is replaced before the next draw, so the total number of possible outcomes remains 26. The probability of drawing M is \(\frac{1}{26}\).
04

Determine the probability of drawing the third letter (A)

Each card is replaced, so the probability of drawing A is also \(\frac{1}{26}\).
05

Determine the probability of drawing the fourth letter (T)

Similarly, with each card replaced, the probability of drawing T is \(\frac{1}{26}\).
06

Calculate the combined probability

The combined probability of drawing G, then M, then A, and finally T is the product of their individual probabilities: \[ \frac{1}{26} \times \frac{1}{26} \times \frac{1}{26} \times \frac{1}{26} = \frac{1}{26^4} \].
07

Simplify the expression to get the final answer

Calculate \(\frac{1}{26^4}\). The probability is \(\frac{1}{456976}\). Hence the correct answer is E. \[ E. \frac{1}{26^4} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation allows us to understand the chances of certain outcomes happening. In this exercise, we wanted to find the probability of drawing the letters G, M, A, and T in that specific order from a set of alphabetical cards. Each card draw is independent, meaning the outcome of one draw does not affect the outcome of the next.

We calculate the probability for each letter individually and then multiply these probabilities together. This is because the events (drawing each letter) are independent. Since there are 26 letters in the alphabet, the probability of drawing any specific letter (like G) is \(\frac{1}{26}\). Since this is true for each letter (G, M, A, T), we multiply these probabilities to find the overall probability of drawing G, then M, then A, and finally T in that order.
Combinatorics
Combinatorics is the branch of mathematics dealing with combinations of objects. In this problem, we use combinatorics to understand and solve the drawing of the cards.

Each card is replaced before the next card is drawn, which means that the total number of possible outcomes remains 26 for each draw. This feature is crucial because it maintains the independence of each draw. Hence, the overall probability is calculated by multiplying the individual probabilities:
- Probability of drawing G: \(\frac{1}{26}\)
- Probability of drawing M: \(\frac{1}{26}\)
- Probability of drawing A: \(\frac{1}{26}\)
- Probability of drawing T: \(\frac{1}{26}\)
Thus, the combined probability is \(\frac{1}{26} \times \frac{1}{26} \times \frac{1}{26} \times \frac{1}{26} = \frac{1}{26^4}\).
Step-by-Step Solution
Breaking down problems into step-by-step solutions helps in understanding complex concepts. Here is how we did it for this problem:

1. **Identify total possible outcomes per draw**: Recognize that each draw has 26 possible outcomes because there are 26 letters.
2. **Determine the probability of drawing each specific letter**: Calculate the probability for one letter at a time. For instance, the probability of drawing G is \(\frac{1}{26}\).
3. **Calculate the combined probability**: Multiply the individual probabilities for each letter to get the combined probability, which is the product of \(\frac{1}{26}\), four times: \(\frac{1}{26^4}\).
Finally, the combined probability tells us that the likelihood of drawing G, M, A, T in that specific order is \(\frac{1}{456976}\).
Mathematics Education
Teaching probability and combinatorics is crucial for a robust understanding of mathematics. This problem demonstrates those concepts in action.

**Key Teaching Points**:
  • Independence of events: Understand that replacing the card keeps the draws independent and maintains the same probability.
  • Multiplication of probabilities: Use the multiplication rule for independent events to find the combined probability.
  • Simplification: Simplify the results to make the probability more comprehensible.
By breaking down the concept and demonstrating step-by-step calculation, students can better grasp the essence and application of probability and combinatorics. This exercise also enhances critical thinking and problem-solving skills in mathematics.

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