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In how many ways can 4 boys and 4 girls be arranged in a row such that boys and girls alternate their positions (that is, boy girl)? (A) 1032 (B) 1152 (C) 1254 (D) 1432

Short Answer

Expert verified
1152 ways (option B).

Step by step solution

01

Identify the pattern of arrangement

To solve this problem, we need the boys and girls to alternate in their seating arrangement. Thus, the possible successful sequences are alternating as either Boy-Girl-Boy-Girl-Boy-Girl-Boy-Girl (BGBGBGBG) or Girl-Boy-Girl-Boy-Girl-Boy-Girl-Boy (GBGBGBGB).
02

Calculate arrangements for BGBGBGBG

Consider the sequence BGBGBGBG. Since we need 4 boys and 4 girls in specific positions, we can arrange the 4 boys in the boy positions in \(4!\) ways and the 4 girls in the girl positions in \(4!\) ways. The number of arrangements for this sequence is calculated as follows:\[4! \times 4! = 24 \times 24 = 576\]
03

Calculate arrangements for GBGBGBGB

Similarly, for the sequence GBGBGBGB, we can arrange the 4 girls in the girl positions in \(4!\) ways and the boys in \(4!\) ways. The number of arrangements for this sequence is:\[4! \times 4! = 24 \times 24 = 576\]
04

Sum up both arrangements

The total number of ways to arrange 4 boys and 4 girls so that they alternate is the sum of the number of ways for each sequence:\[576 + 576 = 1152\]
05

Choose the correct option

Review the answer choices. The total number of ways calculated is 1152, which corresponds to option (B).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
Permutations refer to the different possible arrangements of a set of items where the order of arrangement is significant. In combinatorics, these are essential for calculating how many distinct sequences can arise when placing objects in a particular order.
For instance, with 4 boys and 4 girls needing to be arranged, permutations play a key role. Here, every specific placement of a boy or girl counts as a unique permutation.
  • The number of permutations for arranging 4 boys is given by factorial of 4, written as \(4!\).
  • Similarly, the permutations for arranging 4 girls is given by \(4!\).
Calculating \(4!\) means multiplying the numbers 4, 3, 2, and 1 together. So, \(4! = 4 \times 3 \times 2 \times 1 = 24\). This result shows that there are 24 unique ways to arrange each group of boys or girls, independent of each other.
By further applying this understanding of permutations across combinations like in the exercises given, students can solve more complex arrangement problems effectively.
Arrangement Problems
Arrangement problems are a subset of combinatorial problems where the focus is on assessing possible organizational patterns of a specific set of items. These problems often require analyzing constraints and applying combinatorics to deduce the number of valid sequences or setups.
In the exercise provided, we encountered an arrangement problem with alternating boys and girls. The task was to find valid sequences such as Boy-Girl-Boy-Girl or Girl-Boy-Girl-Boy. Solutions to these issues typically involve identifying patterns and ensuring these patterns align with given constraints.
  • A pattern constraint is that boys and girls alternate, which must be consistently applied to make sure each sequence remains valid.
  • Each alternating pattern leads to a set of permutation calculations as seen in our example, which when solved together, successfully address the constraints of the problem.
Through these organized steps, arrangement problems can be methodically tackled, ensuring a thorough and accurate solution.
Alternating Sequences
Alternating sequences present a specific sequence type where the elements follow a particular rule of alternation. These sequences are characterized by switching back and forth between certain elements, creating a predictable pattern.
For the exercise at hand, alternating sequences come into play with changing placements between boys and girls in a row. The sequences specified with this alternating constraint include Boy-Girl setups as well as Girl-Boy setups. There are two main sequences of interest:
  • Boy-Girl-Boy-Girl (and its continuation).
  • Girl-Boy-Girl-Boy (alternating differently).
These sequences ensure that no two boys or girls sit next to each other, meeting the problem's requirement for alternation.
By understanding how alternating sequences operate, students can better dissect complex arrangement problems, resulting in intuitive and precise solutions. These concepts, combined with an understanding of permutations, facilitate a complete approach to solving many combinatorial challenges.

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Most popular questions from this chapter

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In how many ways can the letters of the word ACUMEN be rearranged such that the vowels always appear together? (A) \(3 ! \cdot 3\) ! (B) \(\frac{6 !}{2 !}\) (C) \(\frac{4 ! \cdot 3 !}{2 !}\) (D) \(4 ! \cdot 3 !\) (E) \(\frac{3 ! \cdot 3 !}{2 !}\)

The retirement plan for a company allows employees to invest in 10 different mutual funds. Six of the 10 funds grew by at least \(10 \%\) over the last year. If Sam randomly selected 4 of the 10 funds, what is the probability that at least 3 of Sam's 4 funds grew by at least \(10 \%\) over the last year? (A) \(\frac{{ }_6 C_3}{{ }_{10} C_4}\) (B) \(\frac{{ }_6 C_3{ }_4 C_1}{{ }_{10} C_4}\) (C) \(\frac{{ }_6 C_{34}{ }_4 C_1+{ }_6 C_4}{{ }_{10} P_4}\) (D) \(\frac{{ }_6 P_3{ }^{\prime} P_1}{{ }_{10} C_4}\) (E) \(\frac{{ }_6 C_3{ }_4 C_1+{ }_6 C_4}{{ }_{10} C_4}\)

In how many ways can the letters of the word GARGANTUNG be rearranged such that all the G's appear together? (A) \(\frac{8 !}{3 ! \cdot 2 ! \cdot 2 !}\) (B) \(\frac{8 !}{2 ! \cdot 2 !}\) (C) \(\frac{8 ! \cdot 3 !}{2 ! \cdot 2 !}\) (D) \(\frac{8 !}{2 ! \cdot 3 !}\) (E) \(\frac{10 !}{3 !-2 ! \cdot 2 !}\)

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