Chapter 6: Problem 9
Show that the set \(\mathbb{C}\) of all complex numbers is a vector space with the usual operations, and find its dimension.
Short Answer
Expert verified
The set \( \mathbb{C} \) is a vector space of dimension 2 over \( \mathbb{R} \).
Step by step solution
01
Define Complex Numbers
The set \( \mathbb{C} \) is the set of all complex numbers. A complex number can be written in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit with \( i^2 = -1 \).
02
Check Closure Properties
To verify closure under addition and scalar multiplication, take two complex numbers \( z_1 = a_1 + b_1i \) and \( z_2 = a_2 + b_2i \). Adding them gives \( (a_1 + a_2) + (b_1 + b_2)i \), which is still in \( \mathbb{C} \). Scalar multiplication with a real number \( c \) gives \( c(a + bi) = ca + cbi \), which is also in \( \mathbb{C} \). Thus, \( \mathbb{C} \) is closed under addition and scalar multiplication.
03
Verify Vector Space Axioms
The set \( \mathbb{C} \) with the operations defined satisfies the following vector space axioms: associative and commutative properties of addition, the existence of an additive identity (0), the existence of additive inverses, distributive properties both for real scalars and within \( \mathbb{C} \), and multiplication by one. These properties confirm that \( \mathbb{C} \) forms a vector space over the real numbers \( \mathbb{R} \).
04
Determine Basis and Dimension
The basis of \( \mathbb{C} \) considered as a vector space over the real numbers is \( \{1, i\} \). Every complex number \( a + bi \) can be written as a linear combination of 1 and \( i \) (i.e., \( a\cdot1 + b\cdot i \)). Since \( 1 \) and \( i \) are linearly independent, they form a basis for \( \mathbb{C} \), which implies the dimension of the space.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Space
Understanding vector spaces is a foundational concept in linear algebra. A vector space is a collection of objects, called vectors, that can be added together and multiplied by numbers, called scalars. These operations adhere to specific rules.
- Addition makes sense within the set. For example, the sum of any two vectors is also a vector.
- Scalar multiplication is similarly defined, allowing any vector to be multiplied by a scalar.
Vector Space Axioms
To verify that a set forms a vector space, it must satisfy certain axioms. These are basically rules that the operations need to follow:
**Closure:** The result of the vector operations should remain within the set.
**Associative and Commutative Laws of Addition:** For any vectors in the set, addition should be both associative \( (u + v) + w = u + (v + w) \) and commutative \( u + v = v + u \).
**Existence of Zero Vector:** There must be a zero vector \( 0 \) such that adding it to any vector \( u \) will not change that vector (i.e., \( u + 0 = u \)).
**Existence of Additive Inverses:** For every vector \( u \), an inverse vector \( -u \) must exist such that \( u + (-u) = 0 \).
**Distributive Laws:** Scalar multiplication must distribute over vector addition \( a(u + v) = au + av \) and addition of scalars \( (a + b)u = au + bu \).
**Multiplicative Identity:** The scalar 1 should act as a multiplicative identity in the set, meaning that multiplying any vector by 1 results in the same vector. The complex numbers comply with these rules, confirming their status as a vector space under usual operations.
**Closure:** The result of the vector operations should remain within the set.
**Associative and Commutative Laws of Addition:** For any vectors in the set, addition should be both associative \( (u + v) + w = u + (v + w) \) and commutative \( u + v = v + u \).
**Existence of Zero Vector:** There must be a zero vector \( 0 \) such that adding it to any vector \( u \) will not change that vector (i.e., \( u + 0 = u \)).
**Existence of Additive Inverses:** For every vector \( u \), an inverse vector \( -u \) must exist such that \( u + (-u) = 0 \).
**Distributive Laws:** Scalar multiplication must distribute over vector addition \( a(u + v) = au + av \) and addition of scalars \( (a + b)u = au + bu \).
**Multiplicative Identity:** The scalar 1 should act as a multiplicative identity in the set, meaning that multiplying any vector by 1 results in the same vector. The complex numbers comply with these rules, confirming their status as a vector space under usual operations.
Basis and Dimension
When discussing vector spaces, the terms "basis" and "dimension" become important. A basis is a set of vectors in this space such that any vector can be expressed as a combination of these basis vectors. Importantly, basis vectors must be linearly independent (no vector in the set can be written as a combination of others).
- For the complex numbers \( \mathbb{C} \), the basis over the real numbers is \([1, i] \). Any complex number \( a + bi \) can be represented as \( a \cdot 1 + b \cdot i \).
- This representation points to the idea of dimension, which is the number of vectors in the basis for the space.