Chapter 2: Problem 20
Define \(\quad T: \mathbb{R}^{n} \rightarrow \mathbb{R}\) by \(T\left(x_{1}, x_{2}, \ldots, x_{n}\right)=x_{1}+x_{2}+\cdots+x_{n} .\) Show that \(T\) is a linear transformation and find its matrix.
Short Answer
Expert verified
\( T \) is a linear transformation with matrix \([1, 1, \ldots, 1]\).
Step by step solution
01
Understand the Definition of a Linear Transformation
A function \( T: \mathbb{R}^{n} \rightarrow \mathbb{R} \) is a linear transformation if it satisfies two properties for any vectors \( \mathbf{u}, \mathbf{v} \in \mathbb{R}^{n} \) and any scalar \( c \in \mathbb{R} \): 1) Additivity: \( T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v}) \). 2) Homogeneity: \( T(c\mathbf{u}) = cT(\mathbf{u}) \).
02
Check Additivity
Let \( \mathbf{u} = (u_1, u_2, \ldots, u_n) \) and \( \mathbf{v} = (v_1, v_2, \ldots, v_n) \). Then, \( \mathbf{u} + \mathbf{v} = (u_1 + v_1, u_2 + v_2, \ldots, u_n + v_n) \). Applying \( T \):\[ T(\mathbf{u} + \mathbf{v}) = (u_1 + v_1) + (u_2 + v_2) + \ldots + (u_n + v_n) \]. This equals:\[ (u_1 + u_2 + \ldots + u_n) + (v_1 + v_2 + \ldots + v_n) = T(\mathbf{u}) + T(\mathbf{v}) \]. Therefore, \( T \) is additive.
03
Check Homogeneity
Let \( \mathbf{u} = (u_1, u_2, \ldots, u_n) \) and \( c \in \mathbb{R} \). Then, \( c\mathbf{u} = (cu_1, cu_2, \ldots, cu_n) \). Applying \( T \):\[ T(c\mathbf{u}) = cu_1 + cu_2 + \ldots + cu_n = c(u_1 + u_2 + \ldots + u_n) = cT(\mathbf{u}) \]. Thus, \( T \) is homogeneous.
04
Conclude Linearity
Since \( T \) satisfies both additivity and homogeneity, \( T \) is a linear transformation.
05
Determine the Matrix Representation
A linear transformation from \( \mathbb{R}^{n} \rightarrow \mathbb{R} \) can be represented by a \( 1 \times n \) matrix \( A \) such that \( A\mathbf{x} = T(\mathbf{x}) \) for any \( \mathbf{x} \in \mathbb{R}^{n} \). Since \( T(\mathbf{x}) = x_1 + x_2 + \ldots + x_n \), the matrix \( A \) would be \( [1, 1, \ldots, 1] \). Hence, the matrix representation of \( T \) is a vector with all ones:\[ A = [1, 1, \ldots, 1] \] with \( n \) entries.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Representation
Matrix representation is a powerful tool that helps to express a linear transformation in a simplified form. For a linear transformation like \( T: \mathbb{R}^{n} \rightarrow \mathbb{R} \), which combines all the components of a vector \( \mathbf{x} \) by summing them up, the matrix representation becomes indispensable to know.
In essence, a matrix is a structured array of numbers, and in this context, it captures how the transformation affects any input vector from \( \mathbb{R}^{n} \). This transformation \( T \) can be expressed by a single row matrix, because it maps from \( n \) dimensions down to 1 dimension:
In essence, a matrix is a structured array of numbers, and in this context, it captures how the transformation affects any input vector from \( \mathbb{R}^{n} \). This transformation \( T \) can be expressed by a single row matrix, because it maps from \( n \) dimensions down to 1 dimension:
- The matrix encapsulates the transformation \( T \) so that for any vector \( \mathbf{x} = (x_1, x_2, \ldots, x_n) \), applying \( T \) is equivalent to multiplying by the matrix \[ A = [1, 1, \ldots, 1] \].
- The result of this multiplication \( A\mathbf{x} \) yields \( T(\mathbf{x}) \), which in this case is \( x_1 + x_2 + \ldots + x_n \).
Additivity in Mathematics
Additivity is a fundamental property of linear transformations, providing insight into the structure and behavior of these functions. In simple terms, a function \( T \) is additive if it satisfies the property:
- \( T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v}) \) for any vectors \( \mathbf{u}, \mathbf{v} \).
- When we calculate \( T(\mathbf{u} + \mathbf{v}) \), it simplifies to a single sum of individual components, showing that \( T \) respects linear addition.
Homogeneity in Linear Algebra
Homogeneity is another cornerstone property of linear transformations, closely tied to the principle of scalability in linear algebra. A function \( T \) demonstrates homogeneity if it respects scalar multiplication as follows:
- \( T(c\mathbf{u}) = cT(\mathbf{u}) \) for any scalar \( c \) and vector \( \mathbf{u} \).
- If we scale \( \mathbf{u} \) to become \( c\mathbf{u} \), applying \( T \) results in \( c(u_1 + u_2 + \ldots + u_n) \), which simplifies to multiplying the sum by the scalar \( c \).