Chapter 2: Problem 18
Let \(\mathbf{x}_{1}\) and \(\mathbf{x}_{2}\) be solutions to the homogeneous system \(A \mathbf{x}=\mathbf{0}\). a. Show that \(\mathbf{x}_{1}+\mathbf{x}_{2}\) is a solution to \(A \mathbf{x}=\mathbf{0}\). b. Show that \(t \mathbf{x}_{1}\) is a solution to \(A \mathbf{x}=\mathbf{0}\) for any scalar \(t\)
Short Answer
Step by step solution
Understand the Given System
Apply Superposition Principle
Demonstrate Linear Combination
Scalar Multiplication Principle
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solutions to Linear Equations
Superposition Principle
- If \( A\mathbf{x}_{1} = \mathbf{0} \) and \( A\mathbf{x}_{2} = \mathbf{0} \), the principle guarantees that \( A(\mathbf{x}_{1} + \mathbf{x}_{2}) = \mathbf{0} \).
- This also implies that if you added or subtracted solutions, you would still stay within the solution set defined by the homogeneous equation.
Linear Combinations
- Finding linear combinations of solutions like \( \mathbf{x}_{1} + \mathbf{x}_{2} \) produces more solutions because of their ability to maintain the equation's balance.
- This further supports the superposition principle as these simple operations won't disturb the zero result of the original equation \( A(\mathbf{x}_{1} + \mathbf{x}_{2}) = \mathbf{0} \).
Scalar Multiplication in Matrices
- If \( A\mathbf{x}_{1} = \mathbf{0} \), multiplying \( \mathbf{x}_{1} \) by a scalar \( t \) results in \( t\mathbf{x}_{1} \).
- Performing matrix multiplication \( A(t\mathbf{x}_{1}) = t(A\mathbf{x}_{1}) = t\mathbf{0} = \mathbf{0} \).