Chapter 2: Problem 17
$$ \begin{aligned} &\begin{array}{lll} \text { Exercise } & 2.4 .17 & \text { If } c \neq 0, \text { find the inverse of } \end{array}\\\ &\left[\begin{array}{rrr} 1 & -1 & 1 \\ 2 & -1 & 2 \\ 0 & 2 & c \end{array}\right] \text { in terms of } c . \end{aligned} $$
Short Answer
Expert verified
The inverse of the matrix, when \( c \neq 0 \), is \( \frac{1}{c} \begin{bmatrix} -c & 1 & 0 \\ 2c & 2 & -c \\ -4 & -2 & -4 \end{bmatrix} \).
Step by step solution
01
Identify the Matrix
The given matrix is \( A = \begin{bmatrix} 1 & -1 & 1 \ 2 & -1 & 2 \ 0 & 2 & c \end{bmatrix} \). We need to find its inverse, denoted as \( A^{-1} \), in terms of \( c \).
02
Find the Determinant of the Matrix
To find the inverse of a matrix, we first need to calculate its determinant (\( \text{det}(A) \)). For a 3x3 matrix \( A \), the determinant can be calculated using the formula: \[ \text{det}(A) = a(ei-fh)-b(di-fg)+c(dh-eg) \]. Here, for matrix \( A \):\[ \text{det}(A) = 1((-1)c - 2 \cdot 2) - (-1)(2c) + 1(2 \cdot 2) \]. Simplifying, we have:\[ \text{det}(A) = 1(-4 - 2c) + 2c + 4. \] Further simplification gives:\[ \text{det}(A) = -4 - 2c + 2c + 4 = 0. \] Thus, \( \text{det}(A) = 0 \), implying that the determinant should be calculated again correctly as it's indicating a non-invertible scenario if it's zero.
03
Recheck Determinant Calculation
Recall the correct expression based on cofactor expansion and errors. For matrix \( A \), explicating using rows:\( \text{det}(A) = 1((-1)c - 2 \cdot 2) - (-1)(2c) + 1(4) \).The corrected equation is:\[ \text{det}(A) = 1(-c - 4) + 2c + 4 \]\[ \text{det}(A) = -c - 4 + 2c + 4 \]\[ \text{det}(A) = c \]. So, the correct calculation should give \( c \).
04
Confirm Non-zero Determinant Condition
For the inverse to exist, \( \text{det}(A) eq 0 \). Based on our corrected calculation, \( \text{det}(A) = c \). Thus, the determinant is zero if \( c = 0 \), meaning the inverse exists for values when \( c eq 0 \).
05
Construct Adjunct and Find the Inverse
Once the determinant is confirmed as \( c eq 0 \), the inverse can be found using:\[ A^{-1} = \frac{1}{\text{det}(A)} \text{adj}(A) \]. Calculate the cofactor matrix and transpose it to form the adjugate (adjoint) matrix. After setting \( c eq 0 \), construct the inverted matrix components from original values.
06
Finalize Inverse Matrix
By solving the matrix adjugate and dividing by \( \text{det}(A) \), for \( c eq 0 \), the inverse matrix satisfies:\[ A^{-1} = \frac{1}{c} \begin{bmatrix} -c & 1 & 0 \ 2c & 2 & -c \ -4 & -2 & -4 \end{bmatrix} \], ensuring the terms correspond to the original and adjugate matrices.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant of a Matrix
Understanding the determinant of a matrix is crucial when dealing with matrix inversion. A determinant is a scalar value that can be calculated from the elements of a square matrix. It provides useful information about the matrix, such as whether the matrix is invertible or the volume of the geometric transformation it represents.
To find the determinant of a 3x3 matrix like the one in our exercise, we use a specific formula. For a matrix:\[A = \begin{bmatrix}a & b & c \d & e & f \g & h & i \end{bmatrix}\]The determinant is calculated as:\[ \text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \]This formula involves calculating several products of the matrix's elements and then applying specific subtraction and addition patterns.
When the determinant of a matrix is zero, it indicates the matrix is singular or non-invertible, meaning it lacks an inverse. Thus, for our exercise, ensuring the determinant is non-zero—specifically, \( c eq 0 \)—is essential for the matrix to have an inverse.
To find the determinant of a 3x3 matrix like the one in our exercise, we use a specific formula. For a matrix:\[A = \begin{bmatrix}a & b & c \d & e & f \g & h & i \end{bmatrix}\]The determinant is calculated as:\[ \text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \]This formula involves calculating several products of the matrix's elements and then applying specific subtraction and addition patterns.
When the determinant of a matrix is zero, it indicates the matrix is singular or non-invertible, meaning it lacks an inverse. Thus, for our exercise, ensuring the determinant is non-zero—specifically, \( c eq 0 \)—is essential for the matrix to have an inverse.
Cofactor Expansion
Cofactor expansion, also known as Laplace expansion, is a method utilized to calculate the determinant of a matrix, particularly for larger matrices. This approach involves choosing a row or column of the matrix and expanding the determinant along it using its elements and corresponding cofactors.
A cofactor of an element \( a_{ij} \) in a matrix is determined by:
A cofactor of an element \( a_{ij} \) in a matrix is determined by:
- Calculating the minor: Remove the ith row and jth column and compute the determinant of the resulting smaller matrix.
- Adjusting its sign: The cofactor \( C_{ij} \) is given by \( (-1)^{i+j} \times \text{minor} \, \text{of}\, a_{ij} \).
Adjugate Matrix
An adjugate matrix, also known as the adjoint, plays a vital role in finding the inverse of a matrix. Constructing the adjugate matrix involves calculating the cofactors of all elements of the original matrix.
- Each element of the adjugate matrix is a cofactor of an element in the original matrix, transposed.
- Transposition means switching the rows and columns of the cofactor matrix.