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Let \(\mathbf{u}\) and \(\mathbf{v}\) be vectors in an inner product space \(V\). a. Expand \(\langle 2 \mathbf{u}-7 \mathbf{v}, 3 \mathbf{u}+5 \mathbf{v}\rangle\). b. Expand \(\langle 3 \mathbf{u}-4 \mathbf{v}, 5 \mathbf{u}+\mathbf{v}\rangle\) c. Show that \(\|\mathbf{u}+\mathbf{v}\|^{2}=\|\mathbf{u}\|^{2}+2\langle\mathbf{u}, \mathbf{v}\rangle+\|\mathbf{v}\|^{2}\). d. Show that \(\|\mathbf{u}-\mathbf{v}\|^{2}=\|\mathbf{u}\|^{2}-2\langle\mathbf{u}, \mathbf{v}\rangle+\|\mathbf{v}\|^{2}\).

Short Answer

Expert verified
a. \(6\|\mathbf{u}\|^2 - 11\langle \mathbf{u}, \mathbf{v} \rangle - 35\|\mathbf{v}\|^2\); b. \(15\|\mathbf{u}\|^2 - 17\langle \mathbf{u}, \mathbf{v} \rangle - 4\|\mathbf{v}\|^2\); c. Proven; d. Proven.

Step by step solution

01

Expand the first inner product

Apply the distributive and linear properties of inner products. \[ \langle 2\mathbf{u} - 7\mathbf{v}, 3\mathbf{u} + 5\mathbf{v} \rangle = 2\langle \mathbf{u}, 3\mathbf{u} \rangle + 2\langle \mathbf{u}, 5\mathbf{v} \rangle - 7\langle \mathbf{v}, 3\mathbf{u} \rangle - 7\langle \mathbf{v}, 5\mathbf{v} \rangle \] Simplify each term using linearity:\[ = 6\langle \mathbf{u}, \mathbf{u} \rangle + 10\langle \mathbf{u}, \mathbf{v} \rangle - 21\langle \mathbf{v}, \mathbf{u} \rangle - 35\langle \mathbf{v}, \mathbf{v} \rangle \] Recognizing symmetry of inner product, \( \langle \mathbf{u}, \mathbf{v} \rangle = \langle \mathbf{v}, \mathbf{u} \rangle \):\[ = 6\|\mathbf{u}\|^2 - 11\langle \mathbf{u}, \mathbf{v} \rangle - 35\|\mathbf{v}\|^2 \]
02

Expand the second inner product

Using distributive and linear properties again: \[ \langle 3\mathbf{u} - 4\mathbf{v}, 5\mathbf{u} + \mathbf{v} \rangle = 3\langle \mathbf{u}, 5\mathbf{u} \rangle + 3\langle \mathbf{u}, \mathbf{v} \rangle - 4\langle \mathbf{v}, 5\mathbf{u} \rangle - 4\langle \mathbf{v}, \mathbf{v} \rangle \] Simplify each term: \[ = 15\langle \mathbf{u}, \mathbf{u} \rangle + 3\langle \mathbf{u}, \mathbf{v} \rangle - 20\langle \mathbf{v}, \mathbf{u} \rangle - 4\langle \mathbf{v}, \mathbf{v} \rangle \] And recognizing symmetry: \[ = 15\|\mathbf{u}\|^2 - 17\langle \mathbf{u}, \mathbf{v} \rangle - 4\|\mathbf{v}\|^2 \]
03

Prove the identity for \( \|\mathbf{u} + \mathbf{v}\|^2 \)

By definition, \( \|\mathbf{u} + \mathbf{v}\|^2 = \langle \mathbf{u} + \mathbf{v}, \mathbf{u} + \mathbf{v} \rangle \). Expand it:\[ = \langle \mathbf{u}, \mathbf{u} \rangle + \langle \mathbf{u}, \mathbf{v} \rangle + \langle \mathbf{v}, \mathbf{u} \rangle + \langle \mathbf{v}, \mathbf{v} \rangle \] Using symmetry again: \[ = \|\mathbf{u}\|^2 + 2\langle \mathbf{u}, \mathbf{v} \rangle + \|\mathbf{v}\|^2 \]
04

Prove the identity for \( \|\mathbf{u} - \mathbf{v}\|^2 \)

Similarly, by definition, \( \|\mathbf{u} - \mathbf{v}\|^2 = \langle \mathbf{u} - \mathbf{v}, \mathbf{u} - \mathbf{v} \rangle \). Expand it:\[ = \langle \mathbf{u}, \mathbf{u} \rangle - \langle \mathbf{u}, \mathbf{v} \rangle - \langle \mathbf{v}, \mathbf{u} \rangle + \langle \mathbf{v}, \mathbf{v} \rangle \] Using symmetry once more:\[ = \|\mathbf{u}\|^2 - 2\langle \mathbf{u}, \mathbf{v} \rangle + \|\mathbf{v}\|^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Algebra
Vector algebra is an essential part of understanding inner product spaces, which provide a framework to handle angles, lengths, and projections of vectors. In this context, vectors can be manipulated similarly to numbers, following specific rules known as vector operations.

One fundamental operation is vector addition, where two vectors are combined into a new vector by adding corresponding components. If you have vectors \( \mathbf{u} \) and \( \mathbf{v} \), their sum is given by \( \mathbf{u} + \mathbf{v} \).

Another critical operation is scalar multiplication, where a vector is multiplied by a real number (scalar), resulting in a vector that points in the original direction but scaled in magnitude. For instance, multiplying a vector \( \mathbf{u} \) by a scalar \( c \) gives \( c\mathbf{u} \).
  • Scalar multiplication expands or contracts a vector.
  • Vector addition combines vectors into a resultant vector.
These operations follow certain laws, like the commutative and associative laws for addition, and the distributive law for scalar multiplication.
Linear Properties
Linear properties in inner product spaces include two main laws: linearity in the first component and linearity in the second component of the inner product. These properties help simplify calculations and prove that operations maintain the structure of the space.

When dealing with vectors \( \mathbf{u}, \mathbf{v}, \) and \( \mathbf{w} \), and scalars \(a\) and \(b\), these properties state that:
  • Linearity in the first component: \( \langle a \mathbf{u} + b \mathbf{v}, \mathbf{w} \rangle = a \langle \mathbf{u}, \mathbf{w} \rangle + b \langle \mathbf{v}, \mathbf{w} \rangle \)
  • Linearity in the second component: \( \langle \mathbf{u}, a \mathbf{v} + b \mathbf{w} \rangle = a \langle \mathbf{u}, \mathbf{v} \rangle + b \langle \mathbf{u}, \mathbf{w} \rangle \)

These properties are fundamental in manipulating expressions involving inner products, such as in simplifying expressions or proving certain vector space theorems. The linear properties allow us to distribute scalars and inner products over addition, which makes the computations much simpler.
Inner Product Symmetry
The symmetry property of the inner product states that the order of vectors within the inner product can be swapped without changing the result. For vectors \( \mathbf{u} \) and \( \mathbf{v} \) in an inner product space, this property is expressed as:

\( \langle \mathbf{u}, \mathbf{v} \rangle = \langle \mathbf{v}, \mathbf{u} \rangle \).

This means that the inner product is reflexive and does not depend on the order of its arguments. Symmetry is particularly crucial when simplifying expressions involving multiple terms.
  • Exploiting symmetry can reduce computational complexity.
  • It ensures the consistency of the inner product formulation.

For example, in expanding \( \langle 2\mathbf{u} - 7\mathbf{v}, 3\mathbf{u} + 5\mathbf{v} \rangle \), symmetry was utilized to equate \( \langle \mathbf{u}, \mathbf{v} \rangle \) to \( \langle \mathbf{v}, \mathbf{u} \rangle \). By leveraging this property, calculations become more straightforward, ensuring that expressions can be simplified consistently across various computations.

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Most popular questions from this chapter

\(V\) denotes a finite dimensional inner product space. Let \(T: V \rightarrow V\) be a linear operator. Show that any two of the following conditions implies the third: 1\. \(T\) is symmetric. 2\. \(T\) is an involution \(\left(T^{2}=1_{V}\right)\). 3\. \(T\) is an isometry. [Hint: In all cases, use the definition $$ \langle\mathbf{v}, T(\mathbf{w})\rangle=\langle T(\mathbf{v}), \mathbf{w}\rangle $$ of a symmetric operator. For (1) and \((3) \Rightarrow(2),\) use the fact that, if \(\left\langle T^{2}(\mathbf{v})-\mathbf{v}, \mathbf{w}\right\rangle=0\) for all \(\mathbf{w}\), then \(T^{2}(\mathbf{v})=\mathbf{v}\).]

Let \(\mathbf{n} \neq \mathbf{0}\) and \(\mathbf{w} \neq \mathbf{0}\) be nonparallel vectors in \(\mathbb{R}^{3}\) (as in Chapter 4). a. Show that \(\left\\{\mathbf{n}, \mathbf{n} \times \mathbf{w}, \mathbf{w}-\frac{\mathbf{n} \cdot \mathbf{w}}{\|\mathbf{n}\|^{2}} \mathbf{n}\right\\}\) is an orthogo- nal basis of \(\mathbb{R}^{3}\). b. Show that \(\operatorname{span}\left\\{\mathbf{n} \times \mathbf{w}, \mathbf{w}-\frac{\mathbf{n} \cdot \mathbf{w}}{\|\mathbf{n}\|^{2}} \mathbf{n}\right\\}\) is the plane through the origin with normal \(\mathbf{n}\).

a. Let \(S\) denote a set of vectors in a finite dimensional inner product space \(V,\) and suppose that \(\langle\mathbf{u}, \mathbf{v}\rangle=0\) for all \(\mathbf{u}\) in \(S\) implies \(\mathbf{v}=\mathbf{0} .\) Show that \(V=\operatorname{span} S .\) [Hint: Write \(U=\operatorname{span} S\) and use Theorem \(10.2 .6 .]\) b. Let \(A_{1}, A_{2}, \ldots, A_{k}\) be \(n \times n\) matrices. Show that the following are equivalent. i. If \(A_{i} \mathbf{b}=\mathbf{0}\) for all \(i\) (where \(\mathbf{b}\) is a column in \(\left.\mathbb{R}^{n}\right),\) then \(\mathbf{b}=\mathbf{0}\) ii. The set of all rows of the matrices \(A_{i}\) spans \(\mathbb{R}^{n}\)

If \(T: V \rightarrow V\) is symmetric, write \(T^{-1}(W)=\\{\mathbf{v} \mid T(\mathbf{v})\) is in \(W\\}\). Show that \(T(U)^{\perp}=T^{-1}\left(U^{\perp}\right)\) holds for every subspace \(U\) of \(V\).

\(V\) denotes a finite dimensional inner product space. If \(T\) is an isometry, show that \(a T\) is an isometry if and only if \(a=\pm 1\).

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