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Suppose that you want to test the hypothesis that a coin has a probability of \(1 / 2\) of coming up heads when you flip it. You flip it 5 times and it comes up heads every time. How likely is it that you would see a pattern of 5 heads in a row if true probability of coming up heads is \(1 / 2 ?\)

Short Answer

Expert verified
The probability of flipping 5 heads in a row with a fair coin is \( \frac{1}{32} \) or 0.03125.

Step by step solution

01

Define the Hypothesis

We are testing the hypothesis that the coin is fair, meaning there is a probability of \( \frac{1}{2} \) of landing heads. Null hypothesis (\( H_0 \)): The coin is fair. Alternative hypothesis (\( H_a \)): The coin is not fair.
02

Calculate the Probability for One Flip

Given the hypothesis, the probability of getting heads on a single flip is \( \frac{1}{2} \).
03

Calculate the Probability for Five Independent Flips

To find the probability of getting 5 heads in a row, when each flip follows a binomial distribution, multiply the probability of getting a head in a single flip by itself five times: \( \left( \frac{1}{2} \right)^5 \).
04

Compute the Result

Calculate \( \left( \frac{1}{2} \right)^5 = \frac{1}{32} \). This represents the likelihood of flipping heads five times in a row with a fair coin.
05

Interpret the Result

The probability of \( \frac{1}{32} \) or approximately 0.03125 indicates that observing 5 consecutive heads is quite unlikely, but not impossible under the assumption of a fair coin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Binomial Distribution
Binomial distribution is a fundamental concept in probability theory that models the number of successes in a sequence of independent experiments. Each experiment, or trial, has only two possible outcomes - often termed "success" and "failure". It’s like flipping a coin where you either get heads or tails.

In the context of our exercise, each flip of the coin is an independent trial with a probability of success (getting heads) being \( \frac{1}{2} \). When we talk about the binomial distribution, we're interested in finding out how probable it is to achieve a certain number of successes (in our case, 5 heads) across several trials (5 flips).
- This distribution is characterized by two parameters:
  • \( n \) - the number of independent trials, here it is 5.
  • \( p \) - the probability of success on an individual trial, which is \( \frac{1}{2} \).
The likelihood of seeing a specific number of successes can be calculated using the binomial probability formula, but since the question involves all successes (5 consecutive heads), we simplify it by computing \( \left(\frac{1}{2}\right)^5 \). This gives us the straightforward probability of seeing all heads in these series of flips.
What is a Null Hypothesis?
The null hypothesis is a crucial element in hypothesis testing as it sets the basis for the initial assumption in a statistical test. It states that there is no effect or no difference, essentially asserting the "status quo."

In our example, the null hypothesis \( {H_0} \) proposes that the coin is fair, which implies that the probability of landing on heads is exactly \( \frac{1}{2} \). This serves as our default assumption which we attempt to test.

- Here are some key points to remember:
  • The null hypothesis is assumed true until evidence suggests otherwise.
  • The alternative hypothesis (\( {H_a} \)) is what you might conclude if you find substantial evidence against the null hypothesis.
  • Rejecting the null hypothesis involves observing an unlikely pattern under the assumption that it is true.
When we observe our 5 heads in row, we question whether this aligns with the assumption of having a fair coin. The probability calculation helps us determine if this observed pattern is statistically significant.
Calculating Probability for Coin Flips
Probability calculation involves determining the likelihood of a particular outcome among all possible outcomes. To assess how likely it is to observe 5 heads in a row using a fair coin, we approach this through the lens of binomial probability.

The probability of flipping a head in a single trial is \( \frac{1}{2} \). Since the flips are independent, to find the probability of consecutive outcomes (i.e., five heads), we multiply the probability of success on each trial by itself 5 times, which is calculated as \( \left( \frac{1}{2} \right)^5 \).

- Let’s break that down:
  • Each flip has a \( \frac{1}{2} \) chance of being heads.
  • Multiply \( \frac{1}{2} \) by itself 5 times to account for each flip contributing to the outcome: \( \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \).
This calculation results in \( \frac{1}{32} \), or approximately 0.03125, denoting that getting 5 heads consecutively with a fair coin isn't highly probable, though certainly not impossible. Such insights help us interpret the results of our hypothesis test.

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