Chapter 8: Problem 2
Find the total differential, given (a) \(z=3 x^{2}+x y-2 y^{3}\) \((b) U=2 x_{1}+9 x_{1} x_{2}+x_{2}^{2}\)
Short Answer
Expert verified
The total differentials are: (a) \( dz = (6x + y) \, dx + (x - 6y^2) \, dy \), (b) \( dU = (2 + 9x_2) \, dx_1 + (9x_1 + 2x_2) \, dx_2 \).
Step by step solution
01
Understand the Problem
We need to find the total differential for two functions. The total differential of a function of two variables is a way to approximate how the function changes, taking into account changes in both variables.
02
Find Partial Derivatives for Part (a)
For the function given in part (a), \( z=3x^2+xy-2y^3 \), we first need to find the partial derivatives with respect to \( x \) and \( y \). The partial derivative with respect to \( x \) is \( \frac{\partial z}{\partial x} = 6x + y \). The partial derivative with respect to \( y \) is \( \frac{\partial z}{\partial y} = x - 6y^2 \).
03
Write the Total Differential for Part (a)
The total differential \( dz \) is given by: \[ dz = \frac{\partial z}{\partial x} \cdot dx + \frac{\partial z}{\partial y} \cdot dy \] Substituting the partial derivatives: \( dz = (6x + y) \, dx + (x - 6y^2) \, dy \).
04
Find Partial Derivatives for Part (b)
For the function given in part (b), \( U = 2x_1 + 9x_1x_2 + x_2^2 \), we need to find the partial derivatives with respect to \( x_1 \) and \( x_2 \). The partial derivative with respect to \( x_1 \) is \( \frac{\partial U}{\partial x_1} = 2 + 9x_2 \). The partial derivative with respect to \( x_2 \) is \( \frac{\partial U}{\partial x_2} = 9x_1 + 2x_2 \).
05
Write the Total Differential for Part (b)
The total differential \( dU \) is given by: \[ dU = \frac{\partial U}{\partial x_1} \cdot dx_1 + \frac{\partial U}{\partial x_2} \cdot dx_2 \] Substituting the partial derivatives: \( dU = (2 + 9x_2) \, dx_1 + (9x_1 + 2x_2) \, dx_2 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
Partial derivatives are a cornerstone concept in multivariable calculus, especially when dealing with functions of more than one variable. They represent how a function changes with respect to one of its variables, while the other variables are held constant.
- For a function of two variables, such as the one given in part (a) \( z = 3x^2 + xy - 2y^3 \), partial derivatives are calculated with respect to \( x \) and \( y \).
- The process involves treating one variable as constant while differentiating with respect to the other.
- In step 2 of the solution, the partial derivative of \( z \) with respect to \( x \) is \( \frac{\partial z}{\partial x} = 6x + y \) and with respect to \( y \) is \( \frac{\partial z}{\partial y} = x - 6y^2 \).
- This shows how \( z \) changes if just \( x \) or \( y \) varies independently.
Multivariable Calculus
Multivariable calculus is a branch of mathematics that deals with functions of more than one variable. It extends the concepts of differential calculus to higher dimensions.
- Functions in multivariable calculus can describe complex systems involving multiple interacting variables.
- In this exercise, functions with two variables like \( z = 3x^2 + xy - 2y^3 \) and \( U = 2x_1 + 9x_1x_2 + x_2^2 \) demonstrate multivariable functions.
- To study these functions, we explore properties like partial derivatives and total differentials.
- Using these tools, we determine how small changes in multiple variables can affect the overall outcome of the function.
Differential Approximation
Differential approximation is a method used to estimate the change in a function due to small changes in its variables. Using total differentials provides a powerful tool for this approximation.
- The total differential for a function gives an approximation of the change in the function as the variables undergo small changes.
- In part (a), the total differential \( dz \) is expressed as \( dz = (6x + y) \, dx + (x - 6y^2) \, dy \).
- This expression combines changes in both \( x \) and \( y \) to approximate the resultant change in \( z \).
- Similarly, in part (b), the total differential \( dU = (2 + 9x_2) \, dx_1 + (9x_1 + 2x_2) \, dx_2 \) provides an approximation for changes in \( U \).