Chapter 10: Problem 3
If \(y\) is related to \(x\) by \(y=x^{k},\) how will the rates of growth \(r_{y}\) and \(r_{x},\) be related?
Short Answer
Expert verified
\( r_y = kx^{k-1} \cdot r_x \): The rate of growth of \( y \) is \( kx^{k-1} \) times the rate of growth of \( x \).
Step by step solution
01
Understanding the Relationship
We are given that the relationship between \(y\) and \(x\) is defined by \(y = x^k\). This implies that \(y\) is a power of \(x\). Here, \(k\) is a constant exponent, and we are interested in finding how the rates of growth of \(y\) (denoted as \(r_y\)) and the rates of growth of \(x\) (denoted as \(r_x\)) relate to each other.
02
Define Rates of Growth
The rate of growth \( r_x \) of \( x \) is defined as the derivative \(\frac{dx}{dt}\), while the rate of growth \( r_y \) of \( y \) is defined as \(\frac{dy}{dt}\). We need to establish how \( \frac{dy}{dt} \) relates to \( \frac{dx}{dt} \).
03
Differentiate the Given Function
To find \( \frac{dy}{dt} \), we differentiate \( y = x^k \) with respect to \( t \).The chain rule gives:\[\frac{dy}{dt} = \frac{d}{dt}(x^k) = kx^{k-1} \cdot \frac{dx}{dt}\]
04
Express the Relationship Between Rates
From the expression derived in the previous step, we can write the rate of growth of \( y \) in terms of the rate of growth of \( x \):\[ \frac{dy}{dt} = kx^{k-1} \cdot \frac{dx}{dt}\]This shows that \( r_y = kx^{k-1} \cdot r_x \). Thus, the rate of growth of \( y \) is proportional to the rate of growth of \( x \) multiplied by \( kx^{k-1} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus. It allows us to differentiate composite functions. In our exercise, we have the function relationship \( y = x^k \). This is a simple case where we treat \( y \) as a function of \( x \), and \( x \) as a function of time \( t \).
The chain rule helps us find the derivative of a function that is nested within another function. The principle can be phrased as: "To differentiate the outer function, multiply the derivative of the outer function by the derivative of the inner function."
The chain rule helps us find the derivative of a function that is nested within another function. The principle can be phrased as: "To differentiate the outer function, multiply the derivative of the outer function by the derivative of the inner function."
- First, identify the outer function; here, it's \( x^k \).
- Next, differentiate \( x^k \) with respect to \( x \), using power rule, making it \( kx^{k-1} \).
- Then, multiply this by the derivative of \( x \) with respect to \( t \), yielding the composition \( kx^{k-1} \cdot \frac{dx}{dt} \).
Power Function
Power functions like \( y = x^k \) are mathematical expressions where a variable \( x \) is raised to a constant power \( k \). Understanding how to differentiate these functions is crucial, as they commonly appear in polynomial equations and many physical laws.
To find the derivative of a power function, we use the "Power Rule," a cornerstone of derivative calculus. This rule states that for \( y = x^n \), its derivative with respect to \( x \) is \( nx^{n-1} \).
In practice, this means:
To find the derivative of a power function, we use the "Power Rule," a cornerstone of derivative calculus. This rule states that for \( y = x^n \), its derivative with respect to \( x \) is \( nx^{n-1} \).
In practice, this means:
- If \( y = x^k \), then \( \frac{d}{dx}(x^k) = kx^{k-1} \).
- This helps us determine the rate at which \( y \) changes with \( x \).
Rates of Growth
Rates of growth refer to how quickly one quantity changes in response to a change in another quantity. In our context, we have \( r_y\) as the rate of growth of \( y \) and \( r_x \) as the rate of growth of \( x \).
The main task is to relate \( r_y = \frac{dy}{dt} \) to \( r_x = \frac{dx}{dt} \). Using differentiation, specifically the chain rule applied to a power function, we found that:
The main task is to relate \( r_y = \frac{dy}{dt} \) to \( r_x = \frac{dx}{dt} \). Using differentiation, specifically the chain rule applied to a power function, we found that:
- \( \frac{dy}{dt} = kx^{k-1} \cdot \frac{dx}{dt} \).
- Thus, \( r_y = k x^{k-1} \times r_x \).