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Which would be hardest for you to give up: Your computer or your television? In a survey of 1677 U.S. Internet users, \(74 \%\) of the young tech elite (average age of 22 ) say their computer would be very hard to give up (PC Magazine, February 3, 2004). Only 48\% say their television would be very hard to give up. a. Develop a \(95 \%\) confidence interval for the proportion of the young tech elite that would find it very hard to give up their computer. b. Develop a \(99 \%\) confidence interval for the proportion of the young tech elite that would find it very hard to give up their television. c. In which case, part (a) or part (b), is the margin of error larger? Explain why.

Short Answer

Expert verified
The 95% confidence interval for the proportion of young tech elite that would find it very hard to give up their computer is (0.7204, 0.7596), while the 99% confidence interval for those who would find it very hard to give up their television is (0.454, 0.506). The margin of error is larger for television (0.0260) compared to computers (0.0196) because the confidence level is higher (99% vs. 95%) and the proportions are different (0.48 vs. 0.74), leading to different standard deviations.

Step by step solution

01

Part (a) Step 1: Calculate the sample proportion for computers

First, calculate the sample proportion (p̂) for the young tech elite that would find it very hard to give up their computer. The sample size is 1677, and 74% say their computer would be very hard to give up. The sample proportion can be calculated as follows: \(p̂ = \frac{x}{n}\) where \(x\) is the number of young tech elite who would find it very hard to give up their computer, and \(n\) is the total number of U.S. Internet users surveyed. \(p̂ = \frac{0.74 \times 1677}{1677} = 0.74\)
02

Part (a) Step 2: Calculate the 95% confidence interval for computers

Next, we will calculate the margin of error (ME) for the 95% confidence interval. To do this, we first need to find the standard deviation, which was calculated using the following formula: \(standard deviation = \sqrt{\frac{p̂(1-p̂)}{n}}\) Now, we can calculate the margin of error: \(ME = z \times standard deviation\) For a 95% confidence interval, the z-value (critical value) is 1.96. We plug in the values and get the margin of error as: \(ME = 1.96 \times \sqrt{\frac{0.74(1-0.74)}{1677}} = 0.0196\) Finally, we find the confidence interval: \(CI = (p̂ - ME, p̂ + ME) = (0.74 - 0.0196, 0.74 + 0.0196) = (0.7204, 0.7596)\) The 95% confidence interval for the proportion of the young tech elite that would find it very hard to give up their computer is (0.7204, 0.7596).
03

Part (b) Step 1: Calculate the sample proportion for television

We follow the same steps as part (a) and begin by calculating the sample proportion (p̂) for the young tech elite that would find it very hard to give up their television. The sample size is 1677, and 48% say their television would be very hard to give up: \(p̂ = \frac{0.48 \times 1677}{1677} = 0.48\)
04

Part (b) Step 2: Calculate the 99% confidence interval for television

To calculate the margin of error (ME) for the 99% confidence interval, we will need to find the standard deviation using the same formula as in part (a): \(standard deviation = \sqrt{\frac{p̂(1-p̂)}{n}}\) Now, we calculate the margin of error: \(ME = z \times standard deviation\) For a 99% confidence interval, the z-value (critical value) is 2.576. We plug in the values and get the margin of error as: \(ME = 2.576 \times \sqrt{\frac{0.48(1-0.48)}{1677}} = 0.0260\) Finally, we find the confidence interval: \(CI = (p̂ - ME, p̂ + ME) = (0.48 - 0.0260, 0.48 + 0.0260) = (0.454, 0.506)\) The 99% confidence interval for the proportion of the young tech elite that would find it very hard to give up their television is (0.454, 0.506).
05

Part (c): Compare the margin of errors and explain the difference

Now we will compare the margin of errors of part (a) and part (b): \(ME_{Computers} = 0.0196\) \(ME_{Television} = 0.0260\) The margin of error is larger for part (b) (Television). The reason behind this is twofold: 1. The confidence level is higher in part (b) (99%) compared to part (a) (95%). As the confidence level increases, the margin of error also increases, in order to provide a larger range for our estimation. 2. The proportions are different in part (a) and part (b) (0.74 vs. 0.48). This means that the standard deviation for the two groups would be different, as it is dependent on the proportion. This difference in standard deviation could also contribute to the difference in the margin of error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values, derived from the sample data, which is likely to contain the population parameter. In simpler terms, it's an estimated range that we believe, with a certain level of confidence, contains the true proportion or average of a population. This concept is essential in statistics because it helps us understand how much we can trust the sample data when making inferences about the entire population.

Confidence intervals are defined by two main components: the confidence level and the margin of error. The confidence level, expressed as a percentage (for example, 95% or 99%), indicates how confident we are that the interval includes the population parameter. A 95% confidence level means that if we repeated the sampling process 100 times, we would expect the true population parameter to lie within the interval 95 times out of 100.
  • The lower bound of the interval shows the smallest estimate.
  • The upper bound of the interval shows the largest estimate.
These bounds are calculated based on the sample data and a critical value from the standard normal distribution, which corresponds to the desired confidence level.
Margin of Error
The margin of error measures the extent of possible error in the sample statistics. It reflects how precisely a statistic computed from sample data estimates the true population parameter. While interpreting confidence intervals, the margin of error indicates the radius of uncertainty.

To compute the margin of error, we use the formula:\[ ME = z \times \sqrt{\frac{p̂(1-p̂)}{n}} \]where:
  • \( z \) is the critical value that corresponds to the desired confidence level,
  • \( pÌ‚ \) is the sample proportion,
  • \( n \) is the sample size.
The resulting ME is then used to construct the upper and lower bounds of the confidence interval. An essential point to remember is that a higher confidence level or smaller sample size will typically result in a larger margin of error.
Sample Proportion
A sample proportion is a statistic that represents the fraction of the sample that exhibited a particular trait of interest. It is denoted by \( p̂ \) and is calculated using the formula:\[ p̂ = \frac{x}{n} \]where:
  • \( x \) is the number of successes in the sample (e.g., people who found it hard to give up their computers in this exercise),
  • \( n \) is the total number of observations in the sample.


Understanding sample proportions is crucial when estimating population parameters and constructing confidence intervals. With the proportional data, statisticians have a baseline for assessing and predicting broader trends and behaviors across a larger population.Knowing the sample proportion allows us to estimate other statistics, such as the standard deviation, which helps in determining the reliability and variability of our findings, ultimately leading to better confidence interval calculations and analyses.

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Most popular questions from this chapter

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