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For a \(t\) distribution with 16 degrees of freedom, find the area, or probability, in each region. a. To the right of 2.120 b. To the left of 1.337 c. To the left of -1.746 d. To the right of 2.583 e. Between -2.120 and 2.120 f. Between -1.746 and 1.746

Short Answer

Expert verified
For a \(t\) distribution with 16 degrees of freedom, the areas or probabilities in each region are: a) To the right of 2.120: \(P(T > 2.120) = 1 - P(T \leq 2.120)\) b) To the left of 1.337: \(P(T \leq 1.337)\) c) To the left of -1.746: \(P(T \leq -1.746)\) d) To the right of 2.583: \(P(T > 2.583) = 1 - P(T \leq 2.583)\) e) Between -2.120 and 2.120: \(P(-2.120 \leq T \leq 2.120) = P(T \leq 2.120) - P(T \leq -2.120)\) f) Between -1.746 and 1.746: \(P(-1.746 \leq T \leq 1.746) = P(T \leq 1.746) - P(T \leq -1.746)\)

Step by step solution

01

Understand the \(t\) distribution and the CDF

The \(t\) distribution is a probability distribution used for hypothesis testing when the sample size is small or when the population variance is unknown. It has the shape of a bell curve and is symmetric around zero. The CDF gives the probability that a random variable is less than or equal to a given value. For our exercise, we will be using the \(t\)-distribution with 16 degrees of freedom.
02

Find the probabilities for part a, b, c, and d

For each region, we will find the CDF values. a) Right of 2.120: To find the probability to the right of 2.120, we calculate 1 minus the CDF of 2.120. \[P(T > 2.120) = 1 - P(T \leq 2.120)\] b) Left of 1.337: We find the CDF value of 1.337. \[P(T \leq 1.337)\] c) Left of -1.746: We find the CDF value of -1.746. \[P(T \leq -1.746)\] d) Right of 2.583: To find the probability to the right of 2.583, we calculate 1 minus the CDF of 2.583. \[P(T > 2.583) = 1 - P(T \leq 2.583)\]
03

Calculate the probabilities for part e and f

For parts e and f, we will calculate the difference between the appropriate CDF values. e) Between -2.120 and 2.120: The probability is the difference between the CDF values of 2.120 and -2.120. \[P(-2.120 \leq T \leq 2.120) = P(T \leq 2.120) - P(T \leq -2.120) \] f) Between -1.746 and 1.746: The probability is the difference between the CDF values of 1.746 and -1.746. \[P(-1.746 \leq T \leq 1.746) = P(T \leq 1.746) - P(T \leq -1.746) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Understanding the concept of 'degrees of freedom' is crucial when working with statistical distributions, particularly the t-distribution. In the simplest terms, degrees of freedom refer to the number of independent pieces of information available to estimate another piece of data or parameter. Specifically, when you have a dataset, the degrees of freedom usually equal the number of data points minus the number of parameters estimated. For instance, in a t-distribution scenario with 16 degrees of freedom, like our exercise, it implies that the sample size from which the distribution was derived consisted of 17 data points, and one parameter (typically the sample mean) has been estimated.

Why is this important? Because the number of degrees of freedom influences the shape of the t-distribution. With more degrees of freedom, the t-distribution looks more like the standard normal distribution. However, with fewer degrees of freedom, the distribution has fatter tails, meaning there's a higher probability for extreme values. This concept is vital when conducting hypothesis testing or constructing confidence intervals, as it determines how 'spread out' the t-distribution will be and, in turn, affects the critical values needed to make statistical decisions.
Cumulative Distribution Function (CDF)
The cumulative distribution function (CDF) of a random variable is a cornerstone of probability theory. It provides the probability that the variable takes a value less than or equal to a particular number. For example, consider rolling a six-sided die; the CDF at x=4 would give the probability of rolling a 4 or anything less on the die.

In the context of the t-distribution, the CDF evaluates the area under the curve to the left of a specific t-value. This accumulates probabilities from the far left of the distribution up to that t-value, which is essential in hypothesis testing and when making statistical inferences about the mean of a population. Since the t-distribution is symmetric, finding the area to the right of a certain t-value, as in parts (a) and (d) of our exercise, involves subtracting the CDF at that t-value from one to obtain the remaining area under the curve.
Hypothesis Testing
Hypothesis testing is a statistical method used to make inferences about a population parameter based on sample data. It starts with an initial assumption, known as the null hypothesis, which typically suggests that there is no effect or difference. An alternative hypothesis is then considered, positing the existence of an effect or difference.

Then, a test statistic is calculated from the sample data—an observed effect size, for example, and based on a particular distribution; in our exercise, it is the t-distribution. This statistic is then compared to a critical value which corresponds to a predetermined significance level, commonly set at 0.05. If the test statistic falls within a critical range, the null hypothesis may be rejected in favor of the alternative hypothesis.

Our exercise involves calculating the probabilities of observing certain t-values under the t-distribution, which is a fundamental step in the hypothesis testing procedure. By determining these areas or probabilities, researchers can make decisions related to their hypotheses about a population mean when variances are unknown and the sample size is small.

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Most popular questions from this chapter

The National Quality Research Center at the University of Michigan provides a quarterly measure of consumer opinions about products and services (The Wall Street Journal, February 18,2003 ). A survey of 10 restaurants in the Fast Food/Pizza group showed a sample mean customer satisfaction index of \(71 .\) Past data indicate that the population standard deviation of the index has been relatively stable with \(\sigma=5\) a. What assumption should the researcher be willing to make if a margin of error is desired? b. Using \(95 \%\) confidence, what is the margin of error? c. What is the margin of error if \(99 \%\) confidence is desired?

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How large a sample should be selected to provide a \(95 \%\) confidence interval with a margin of error of \(10 ?\) Assume that the population standard deviation is 40

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