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Chapter 6: Problem 18

A(n) _________ variable is defined inside a function and is not accessible outside the function.

Short Answer

Expert verified
Answer: Local variable

Step by step solution

01

Understand the Concept

This description is about the scope of variables in programming. In programming languages, the scope is the portion of the code where a variable can be seen and accessed. Some variables can be accessed throughout the whole program, and some are limited to a specific function or block. We need to fill in the blank with the specific term for variables that are only accessible within the function where they are defined.
02

Identify the Correct Term

From our knowledge of programming, we know that the term describing a variable that is accessible only within the function it is defined in, is "local variable".
03

Complete the Statement

Using the correct term that we've identified, we can fill the blank in the given formula. The completed formula will read: "A local variable is defined inside a function and is not accessible outside the function."

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Most popular questions from this chapter

How would a static local variable be useful?

Unless you explicitly initialize global variables, they are automatically initialized to _________.

Write a function named getNumber that uses a reference parameter variable to accept an integer argument. The function should prompt the user to enter a number in the range of 1 through 100. The input should be validated and stored in the parameter variable.

Locate as many errors as you can. ( Overloaded functions) int getValue() { int inputValue; cout << "Enter an integer: "; cin >> inputValue; return inputValue; } double getValue() { double inputValue; cout << "Enter a floating-point number: "; cin >> inputValue; return inputValue; }

\(\mathrm{T} \quad \mathrm{F} \quad\) Static local variables are not destroyed when a function returns.
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