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Chapter 7: Problem 51

values is a two-dimensional array of floats with 10 rows and 20 columns. Write code that sums all the elements in the array and stores the sum in the variable total.

Short Answer

Expert verified
Answer: To compute the sum of all elements in a 10x20 two-dimensional array, initialize a variable 'total' with a value of 0.0. Then, use a nested loop to traverse through the rows (i-index) and columns (j-index) of the array. Inside the nested loop, access the individual elements of the array using the 'i' and 'j' indices, and add the accessed elements to the 'total' variable.

Step by step solution

01

Initialize the total variable

Before we begin computing the sum of the elements in the array, we need to initialize a variable called 'total' to store the sum. Assign a value of 0.0 to the 'total' variable. `float total = 0.0;`
02

Traverse through the rows using a for loop

We need to access each row of the two-dimensional array. Use a for loop with an integer iterator 'i' initialized at 0. The loop should run while 'i' is less than 10 (the number of rows). `for (int i = 0; i < 10; i++) {` // steps to access elements inside each row will be written here `}`
03

Traverse through the columns using another for loop

Inside the first for loop, create another for loop with an integer iterator 'j' initialized at 0. The second loop should run while 'j' is less than 20 (the number of columns). `for (int j = 0; j < 20; j++) {` // steps to access the array elements and sum them will be written here `}`
04

Access the array elements and sum them

Inside the nested for loop, we can access the individual elements of the two-dimensional array 'values' using the indices 'i' and 'j'. Add the accessed element to the variable 'total'. `total += values[i][j];` The complete code solution should look like this: ``` float total = 0.0; for (int i = 0; i < 10; i++) { for (int j = 0; j < 20; j++) { total += values[i][j]; } } ```

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