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include #include using namespace std; int main() { long seconds; double minutes, hours, day… # (Assume the user enters 36720152. Use a calculator.) #include #include using namespace std; int main() { long seconds; double minutes, hours, days, months, years; cout << "Enter the number of seconds that have\n"; cout << "elapsed since some time in the past and\n"; cout << "I will tell you how many minutes, hours,\n"; cout << "days, months, and years have passed: "; cin >> seconds; minutes = seconds / 60; hours = minutes / 60; days = hours / 24; years = days / 365; months = years * 12; cout << setprecision(4) << fixed << showpoint << right; cout << "Minutes: " << setw(6) << minutes << endl; cout << "Hours: " << setw(6) << hours << endl; cout << "Days: " << setw(6) << days << endl; cout << "Months: " << setw(6) << months << endl; cout << "Years: " << setw(6) << years << endl; return 0; }

Step by step solution

01

Read Input

The code starts by prompting the user to enter the number of seconds, and then reads the input using the 'cin' statement.

02

Conversion calculations

Next, the code performs the following conversion calculations: .minutes = seconds / 60 .hours = minutes / 60 .days = hours / 24 .years = days / 365 .months = years * 12 As per the given input (36720152 seconds), the conversions would be as follows (using a calculator): .minutes = 36720152 / 60 = 611002.5333 .hours = 611002.5333 / 60 = 10183.3755 .days = 10183.3755 / 24 = 424.3073 .years = 424.3073 / 365 = 1.1622 .months = 1.1622 * 12 = 13.9464

03

Display the results

Finally, the code outputs the results with proper formatting using 'cout' statements. The setw(6) ensures proper spacing, while fixed, showpoint, and setprecision(4) ensure that each value is displayed with 4 decimal places: Minutes: 611002.5333 Hours: 10183.3755 Days: 424.3073 Months: 13.9464 Years: 1.1622 These are the minutes, hours, days, months, and years that have passed since 36720152 seconds ago.

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