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In object-oriented programming, a derived class inherits properties and behavior from a base class. This approach allows for code reusability and easier implementation of complex structures. When working with pointers in such cases, it's important to understand if a base class pointer can be assigned the address of a derived class object.

Let's take an example. Suppose we have a base class called Shape and a derived class called Circle. ```cpp class Shape { public: virtual void area() const { // Some implementation } }; class Circle : public Shape { public: void area() const override { // Some implementation } }; ``` Now, let's consider the following code: ```cpp Circle myCircle; Shape* ptrShape = &myCircle ``` In this case, we are creating an object `myCircle` of the derived class Circle and assigning its address to a pointer `ptrShape` of the base class Shape. This is allowed in C++ because the derived class object includes all the properties of the base class. We can use this base class pointer to call functions of the base class that have been inherited or overridden by the derived class.

Based on the example and the analysis, we can conclude that the given statement - "Pointers to a base class may be assigned the address of a derived class object" - is True.