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Does a structure declaration cause a structure variable to be created?

Short Answer

Expert verified
Answer: No, declaring a structure in programming languages like C++ only defines a blueprint for a data type, and does not create a structure variable. To create a structure variable, you need to explicitly declare a variable of the structure type.

Step by step solution

01

Understanding Structure Declaration

A structure declaration in programming languages like C++ is a way to define a user-defined data type, which can group different data types under a single name. It is a blueprint from which the structure variables can be created.
02

Creating a Structure Variable

A structure variable can be created by declaring a variable of the structure type, which is defined by the structure declaration. However, the structure declaration itself does not create a structure variable; it only provides the blueprint.
03

Example of Structure Declaration and Structure Variable

Let's understand through an example. Consider the following structure declaration in C++: struct Student { int roll_no; string name; float GPA; }; This structure declaration defines a blueprint for a data type named 'Student' consisting of an integer (roll_no), a string (name), and a float (GPA). To create a structure variable, we can use the following code: Student s1; Here, 's1' is the structure variable of the type 'Student'. The structure declaration 'Student' does not create a variable itself; only the latter line of code does that.
04

Conclusion

A structure declaration in programming languages like C++ does not cause a structure variable to be created. It only defines a blueprint for a data type from which the structure variables can be created. Creating a structure variable requires explicitly declaring a variable of the structure type, as shown in the example.

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