Problem 28 Assume input is a char array hol... [FREE SOLUTION]

Chapter 10: Problem 28

Assume input is a char array holding a C-string. Write code that counts the number of elements in the array that contain an alphabetic character.

Short Answer

Expert verified

Based on the above step-by-step solution, answer the following question: **Question:** Write a C++ code to count the number of alphabetic characters in a given input char array (C-string). **Answer:** Here is the C++ code that counts the number of alphabetic characters in a given input char array: ```cpp #include #include // For strlen() int main() { char input[] = "Example C-string 123!"; int count = 0; // Loop through the input char array for (int i = 0; i < strlen(input); ++i) { // Check for alphabet (either lower or uppercase) if ((input[i] >= 'A' && input[i] <= 'Z') || (input[i] >= 'a' && input[i] <= 'z')) { count++; } } // Print the count of alphabetic characters std::cout << "Number of alphabetic characters: " << count << std::endl; return 0; } ```

Step by step solution

Initialize variables and loop through the input

First, create a variable "count" to store the number of alphabetic characters found in the C-string. Then, create a loop to iterate through the input array, utilizing its size. ```cpp #include #include // For strlen() int main() { char input[] = "Example C-string 123!"; int count = 0; for (int i = 0; i < strlen(input); ++i) { // Processing goes here } return 0; } ```

Check for alphabetic character

In the loop, use an if-else statement to check if the element at the current index is an uppercase alphabetic character (65-90 in ASCII) or lowercase alphabetic character (97-122 in ASCII). If so, increment the count by 1. ```cpp for (int i = 0; i < strlen(input); ++i) { if ((input[i] >= 'A' && input[i] <= 'Z') || (input[i] >= 'a' && input[i] <= 'z')) { count++; } } ```

Print the count of alphabetic characters

After the loop has processed the whole char array, count will hold the total number of alphabetic characters. Use 'cout' to display the count of alphabetic characters. ```cpp std::cout << "Number of alphabetic characters: " << count << std::endl; ```

Complete Code

Here is the complete code that counts the number of elements in the input array that contain an alphabetic character. ```cpp #include #include // For strlen() int main() { char input[] = "Example C-string 123!"; int count = 0; // Loop through the input char array for (int i = 0; i < strlen(input); ++i) { // Check for alphabet (either lower or uppercase) if ((input[i] >= 'A' && input[i] <= 'Z') || (input[i] >= 'a' && input[i] <= 'z')) { count++; } } // Print the count of alphabetic characters std::cout << "Number of alphabetic characters: " << count << std::endl; return 0; } ```

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91影视

Assume input is a char array holding a C-string. Write code that counts the number of elements in the array that contain an alphabetic character.

Short Answer

Step by step solution

Initialize variables and loop through the input

Check for alphabetic character

Print the count of alphabetic characters

Complete Code

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