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Chapter 8: Problem 19

include #include using namespace std; int main( ) { vector v(10); int i; for (i = 0;鈥� # Is the following program legal? If so, what is the output? #include #include using namespace std; int main( ) { vector v(10); int i; for (i = 0; i < v.size( ); i++) v[i] = i; vector copy; copy = v; v[0] = 42; for (i = 0; i < copy.size( ); i++) cout << copy[i] << " "; cout << endl; return 0; }

Short Answer

Expert verified
The output of the given C++ program is: 0 1 2 3 4 5 6 7 8 9

Step by step solution

01

1. Initialize the vector "v"

First, a vector "v" of size 10 is created, with elements initialized to 0. A variable "i" is declared as well.
02

2. Fill the vector "v" with values

A loop iterates from 0 to the size of the vector "v". During each iteration, the ith element of the vector is set to "i."
03

3. Create a new vector "copy" and copy the elements from "v" to "copy"

Here, a new vector "copy" is created. Then, the elements of vector "v" are assigned to "copy" using the assignment operator. This creates a deep copy of the vector, meaning both vectors have the same elements but are stored in different memory locations.
04

4. Modify the first element of vector "v" and keep the "copy" vector intact

Now, the first element of vector "v" is changed to 42. But this change doesn't affect the "copy" vector because it's a deep copy.
05

5. Iterate through the "copy" vector and print its elements

In this final step, a loop iterates through the "copy" vector and prints its elements on the console, followed by a space. After the loop finishes, a new line is printed. Since the program compiles and runs successfully, it is legal. Now let's find out the output of the program. As per the analysis, the original vector "v" contains elements [42, 1, 2, 3, 4, 5, 6, 7, 8, 9]. The "copy" vector contains elements [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] as it was copied before any changes were made to the vector "v". Hence, the output of the program is: 0 1 2 3 4 5 6 7 8 9

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