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Chapter 14: Problem 1

include using namespace std; void cheers(int n); int main( ) { cheers(3); return 0; } void cheers(int n) { if (n鈥� # What is the output of the following program? #include using namespace std; void cheers(int n); int main( ) { cheers(3); return 0; } void cheers(int n) { if (n == 1) { cout << "Hurray\n"; } else { cout << "Hip "; cheers(n ? 1); } }

Short Answer

Expert verified
Answer: The output of the given C++ program is "Hip Hip Hurray\n".

Step by step solution

01

Identify the Base Case

We'll start by identifying the base case of the recursive function "cheers()". If the input 'n' is equal to 1, the function will print "Hurray\n".
02

Analyze the Recursion

If the input 'n' is not equal to 1, the function will print "Hip " and then call itself with the input decreased by one (cheers(n-1)).
03

Methodically Process the Recursive Calls

Here is the sequence of function calls step by step: 1. cheers(3) is called in the main() function: - Since 3 != 1, prints "Hip ", then calls cheers(2) 2. cheers(2) is called: - Since 2 != 1, prints "Hip ", then calls cheers(1) 3. cheers(1) is called: - Since 1 == 1, prints "Hurray\n"
04

Combine the Outputs

By combining the outputs from each level of the recursive call, we can determine the final output: "Hip Hip Hurray\n" So, the output of the given program will be: Hip Hip Hurray

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Most popular questions from this chapter

If your program produces an error message that says stack overflow, what is a likely source of the error?

Write a recursive void function that takes a single int argument \(n\) and writes the integers \(1,2, \ldots, n\)

Write a recursive void function that has one parameter which is a positive integer and that writes out that number of asterisks '*' to the screen all on one line.

Write a recursive void function that takes a single int argument \(n\) and writes integers \(n, n-1, \ldots, 3,2,1 .\) Hint: Notice that you can get from the code for Self-Test Exercise 4 to that for Self-Test Exercise 5 (or vice versa) by an exchange of as little as two lines.

Write a recursive void function that has one parameter, which is a positive integer. When called, the function writes its argument to the screen backward. That is, if the argument is \(1234,\) it outputs the following to the screen: 4321
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