Chapter 6: Problem 24
\((\star)\) Show that a diagonal matrix \(W\) whose elements satisfy \(0
Short Answer
Expert verified
A diagonal matrix \( W \) with \( 0 < W_{ii} < 1 \) is positive definite. The sum of two positive definite matrices is also positive definite.
Step by step solution
01
Understanding the Problem
We need to prove two things: (1) A diagonal matrix \( W \) with elements satisfying \( 0 < W_{ii} < 1 \) is positive definite. (2) The sum of two positive definite matrices is positive definite.
02
Definitions and Properties
Recall that a matrix is positive definite if for any non-zero vector \( \mathbf{x} \), \( \mathbf{x}^T A \mathbf{x} > 0 \). For a diagonal matrix \( D \), this expression simplifies to \( \sum_{i=1}^{n} D_{ii} x_i^2 \).
03
Proving Diagonal Matrix is Positive Definite
Consider the diagonal matrix \( W \), where diagonal elements satisfy \( 0 < W_{ii} < 1 \). Then \( \mathbf{x}^T W \mathbf{x} = \sum_{i=1}^{n} W_{ii} x_i^2 \). Each term \( W_{ii} x_i^2 > 0 \) for any nonzero \( x_i \) because \( 0 < W_{ii} < 1 \). Therefore, \( \mathbf{x}^T W \mathbf{x} > 0 \) for all non-zero \( \mathbf{x} \), so \( W \) is positive definite.
04
Sum of Two Positive Definite Matrices
Let \( A \) and \( B \) be two positive definite matrices. Then for any non-zero vector \( \mathbf{x} \), we have \( \mathbf{x}^T A \mathbf{x} > 0 \) and \( \mathbf{x}^T B \mathbf{x} > 0 \). Therefore, the sum: \( \mathbf{x}^T (A + B) \mathbf{x} = \mathbf{x}^T A \mathbf{x} + \mathbf{x}^T B \mathbf{x} > 0 \). This implies \( A + B \) is positive definite.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Diagonal Matrix
A diagonal matrix is a square matrix where all elements outside the main diagonal are zero. Only the elements along the diagonal (from the top-left to the bottom-right) can be nonzero. This simplicity makes diagonal matrices very easy to work with, especially in computations.
For example, consider a 3x3 diagonal matrix:
Understanding the structure of a diagonal matrix is crucial for identifying when it's positive definite. A diagonal matrix is positive definite if all the diagonal elements are positive. So if you have elements satisfying the condition \( 0 < W_{ii} < 1 \), like in the exercise above, then you can easily check the positive definite property by ensuring each diagonal term is greater than zero.
For example, consider a 3x3 diagonal matrix:
- The matrix is:
\[\begin{bmatrix}a & 0 & 0 \0 & b & 0 \0 & 0 & c\end{bmatrix}\]
Understanding the structure of a diagonal matrix is crucial for identifying when it's positive definite. A diagonal matrix is positive definite if all the diagonal elements are positive. So if you have elements satisfying the condition \( 0 < W_{ii} < 1 \), like in the exercise above, then you can easily check the positive definite property by ensuring each diagonal term is greater than zero.
Matrix Addition
Matrix addition is a fundamental operation where two matrices of the same dimensions are added together by adding their corresponding elements.
Let's look at an example of how it works:
Let's look at an example of how it works:
- If you have two matrices:
\[A = \begin{bmatrix}1 & 2 \3 & 4\end{bmatrix},\quadB = \begin{bmatrix}5 & 6 \7 & 8\end{bmatrix}\] - Their sum, \( C = A + B \), is:
\[C = \begin{bmatrix}1+5 & 2+6 \3+7 & 4+8\end{bmatrix} = \begin{bmatrix}6 & 8 \10 & 12\end{bmatrix}\]
Vector Multiplication
In linear algebra, vector multiplication refers to operations that involve vectors and matrices. A common multiplication involving vectors is the dot product (or scalar product), calculated as follows:
In matrix contexts, the multiplication \( \mathbf{x}^T A \mathbf{x} \) involves a vector \( \mathbf{x} \) and a matrix \( A \), and it leads to understanding positive definite matrices.
First, you perform \( A \mathbf{x} \), which results in another vector, and then take the dot product of \( \mathbf{x}^T \) with this new vector. This process shows how these operations combine to define if a matrix is positive definite, confirming that this expression is positive for any non-zero vector \( \mathbf{x} \). This helps in many practical applications where stability and certain behaviors of systems need to be guaranteed.
- For vectors \( \mathbf{u} = [u_1, u_2,...,u_n] \) and \( \mathbf{v} = [v_1, v_2,...,v_n] \), the dot product is:
\[\mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + ... + u_nv_n\]
In matrix contexts, the multiplication \( \mathbf{x}^T A \mathbf{x} \) involves a vector \( \mathbf{x} \) and a matrix \( A \), and it leads to understanding positive definite matrices.
First, you perform \( A \mathbf{x} \), which results in another vector, and then take the dot product of \( \mathbf{x}^T \) with this new vector. This process shows how these operations combine to define if a matrix is positive definite, confirming that this expression is positive for any non-zero vector \( \mathbf{x} \). This helps in many practical applications where stability and certain behaviors of systems need to be guaranteed.