/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Show that the inverse of a symme... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the inverse of a symmetric matrix is itself symmetric.

Short Answer

Expert verified
The inverse of a symmetric matrix is also symmetric, due to its identity relations and transpose properties.

Step by step solution

01

Understand Symmetric Matrices

A matrix is symmetric if it is equal to its transpose. That is, for a matrix \( A \), if \( A = A^T \), then \( A \) is symmetric.
02

Recall Properties of Inverses

The inverse of a matrix \( A \), denoted by \( A^{-1} \), satisfies the equation \( A \, A^{-1} = A^{-1} \, A = I \), where \( I \) is the identity matrix.
03

Use the Property of Transpose

The transpose of a product of matrices is the product of their transposes in reverse order. Mathematically, \( (AB)^T = B^T A^T \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Inverse
The concept of the matrix inverse is crucial when solving systems of linear equations and performing other matrix operations. For a given matrix \( A \), its inverse \( A^{-1} \) is a matrix that, when multiplied with \( A \) yields the identity matrix \( I \). This is expressed in the equation: \[A \, A^{-1} = A^{-1} \, A = I\]
  • Not every matrix has an inverse. Only square matrices (same number of rows and columns) that are non-singular (having a non-zero determinant) are invertible.
  • The process of finding an inverse involves using methods like the Gauss-Jordan elimination or the adjoint method, depending on the size and properties of the matrix.
Understanding matrix inversion helps in many mathematical and scientific applications, especially in solving equations where you can transform everything into the form \( X = A^{-1} \, B \), making \( X \) easy to compute once \( A^{-1} \) is known.
Matrix Transpose
The transpose of a matrix is an operation that flips a matrix over its diagonal. For a matrix \( A \), the transpose, denoted \( A^T \), is formed by swapping the rows and columns of \( A \). For example, if\[A = \begin{bmatrix}a & b \c & d\end{bmatrix}\]then\[A^T = \begin{bmatrix}a & c \b & d\end{bmatrix}\]
  • Transposing a matrix twice gives you back the original matrix: \( (A^T)^T = A \).
  • The transpose operation maintains the dimensions of the original matrix, shifting elements but not size.
Transposition is often used in conjunction with other matrix operations as it can simplify expressions and prove certain matrix properties, particularly in symmetric matrices which are equal to their transposes.
Identity Matrix
The identity matrix plays an integral role in linear algebra as it is the "multiplicative identity" of the matrix world, analogous to the number 1 in arithmetic. An identity matrix is a square matrix with ones on the diagonal and zeroes elsewhere. For a 3x3 matrix, this looks like:\[I = \begin{bmatrix}1 & 0 & 0 \0 & 1 & 0 \0 & 0 & 1\end{bmatrix}\]
  • When you multiply any matrix \( A \) by the identity matrix \( I \), you get \( A \) back: \( AI = IA = A \).
  • This property is pivotal when working with inverses, as the defining feature of an inverse matrix \( A^{-1} \) is that \( A \, A^{-1} = I \).
Identity matrices are fundamental in simplifying matrix expressions and act as the matrix equivalent of "doing nothing" to the original matrix, maintaining its dimensions and properties.
Matrix Properties
Matrices come with a range of intrinsic properties that make them both fascinating and useful. Key to understanding these properties is knowing how they interact in various operations:
  • Symmetry: A matrix \( A \) is symmetric if it is equal to its transpose: \( A = A^T \). This allows certain simplifying assumptions in equations and proofs.
  • Commutativity: Generally, matrix multiplication is not commutative, meaning \( AB eq BA \) unless certain conditions are met, such as both matrices being diagonal or themselves equal.
  • Associativity: Matrix multiplication is associative, allowing grouping \( (AB)C = A(BC) \), which is crucial in sequential calculations.
  • Distributivity: Matrices follow distributive laws: \( A(B + C) = AB + AC \) and \( (A + B)C = AC + BC \).
These properties are essential for solving complex mathematical problems and prove particularly useful when analyzing problems related to symmetric and inversed matrices.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In this exercise, we prove that the binomial distribution \((2.9)\) is normalized. First use the definition (2.10) of the number of combinations of \(m\) identical objects chosen from a total of \(N\) to show that $$ \left(\begin{array}{l} N \\ m \end{array}\right)+\left(\begin{array}{c} N \\ m-1 \end{array}\right)=\left(\begin{array}{c} N+1 \\ m \end{array}\right) $$ Use this result to prove by induction the following result $$ (1+x)^{N}=\sum_{m=0}^{N}\left(\begin{array}{l} N \\ m \end{array}\right) x^{m} $$ which is known as the binomial theorem, and which is valid for all real values of \(x\). Finally, show that the binomial distribution is normalized, so that $$ \sum_{m=0}^{N}\left(\begin{array}{l} N \\ m \end{array}\right) \mu^{m}(1-\mu)^{N-m}=1 $$ which can be done by first pulling out a factor \((1-\mu)^{N}\) out of the summation and then making use of the binomial theorem.

( \(\star)\) The uniform distribution for a continuous variable \(x\) is defined by $$ \mathrm{U}(x \mid a, b)=\frac{1}{b-a}, \quad a \leqslant x \leqslant b . $$ Verify that this distribution is normalized, and find expressions for its mean and variance.

\((\star \star)\) Show that the entropy of the multivariate Gaussian \(\mathcal{N}(\mathbf{x} \mid \boldsymbol{\mu}, \boldsymbol{\Sigma})\) is given by $$ \mathrm{H}[\mathbf{x}]=\frac{1}{2} \ln |\boldsymbol{\Sigma}|+\frac{D}{2}(1+\ln (2 \pi)) $$ where \(D\) is the dimensionality of \(\mathrm{x}\).

This exercise demonstrates that the multivariate distribution with maximum entropy, for a given covariance, is a Gaussian. The entropy of a distribution \(p(\mathbf{x})\) is given by $$ \mathrm{H}[\mathbf{x}]=-\int p(\mathbf{x}) \ln p(\mathbf{x}) \mathrm{d} \mathbf{x} $$ We wish to maximize \(\mathrm{H}[\mathbf{x}]\) over all distributions \(p(\mathbf{x})\) subject to the constraints that \(p(\mathbf{x})\) be normalized and that it have a specific mean and covariance, so that $$ \begin{aligned} &\int p(\mathbf{x}) \mathrm{d} \mathbf{x}=1 \\ &\int p(\mathbf{x}) \mathbf{x} \mathrm{d} \mathbf{x}=\boldsymbol{\mu} \\ &\int p(\mathbf{x})(\mathbf{x}-\boldsymbol{\mu})(\mathbf{x}-\boldsymbol{\mu})^{\mathrm{T}} \mathrm{d} \mathbf{x}=\mathbf{\Sigma} . \end{aligned} $$ By performing a variational maximization of (2.279) and using Lagrange multipliers to enforce the constraints \((2.280),(2.281)\), and \((2.282)\), show that the maximum likelihood distribution is given by the Gaussian (2.43).

Consider a \(D\)-dimensional Gaussian random variable \(\mathrm{x}\) with distribution \(\mathcal{N}(\mathbf{x} \mid \boldsymbol{\mu}, \boldsymbol{\Sigma})\) in which the covariance \(\boldsymbol{\Sigma}\) is known and for which we wish to infer the mean \(\boldsymbol{\mu}\) from a set of observations \(\mathbf{X}=\left\\{\mathbf{x}_{1}, \ldots, \mathbf{x}_{N}\right\\}\). Given a prior distribution \(p(\boldsymbol{\mu})=\mathcal{N}\left(\boldsymbol{\mu} \mid \boldsymbol{\mu}_{0}, \boldsymbol{\Sigma}_{0}\right)\), find the corresponding posterior distribution \(p(\boldsymbol{\mu} \mid \mathbf{X}) .\)

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.