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A triangle in an undirected graph is a 3-clique. Show thatTRIANGLEP , whereTRIANGLE=<G>|Gcontainsatriangle.

Short Answer

Expert verified

Three edges connection over based on the theory of polynomial show the length of inlet.

Step by step solution

01

To Turing Machine of Class-P

ClassP:Pis a class of languages that are decidable in polynomial time on a deterministic single 鈥 tape Turing 鈥 machine.

02

Undirected Graph of Clique

Specified language, a triangle is an undirected graph is a3--clique.Now we have to show that TRIANGLEP

Let AbetheTuringmachinethatdecidesTRIANGLE is polynomial timeAcan be described as follows:

:A=''oninputG<V,E>

V denotes set of vertices of the graphG .

E denotes set of edges of the graphG .

For u,v,wV and u<v<wwe enumerate all triples <u,v,w>.Check whether all three edges u,v(v,w)exist in Eor not. If exist then accept.Otherwise reject.鈥

Enumeration of all triple require0(|v|3)time. Checking whether all three edges belong to E take 0(|E|)time.Overall time is 0(|V|3|E|)which is polynomial in the length of the inlets. ThereforeTRIANGLEP . Three edges connection over base on the theory of polynomial show the length of inplet..

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Most popular questions from this chapter

You are given a box and a collection of cards as indicated in the following figure. Because of the pegs in the box and the notches in the cards, each card will fit in the box in either of two ways. Each card contains two columns of holes, some of which may not be punched out. The puzzle is solved by placing all the cards in the box so as to completely cover the bottom of the box (i.e., every hole position is blocked by at least one card that has no hole there). It represents a card and this collection of cards has a solution}. Show that PUZZLE is NP-complete.

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