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LetCNFH= is a satisfiable CNF-formula where each clause contains any number of literals, but at most one negated literal}. Show that CNFH?P.

Short Answer

Expert verified

This situation will be held true for CNFH∈P.

Step by step solution

01

Step 1:To find value of CNF

⟨φ⟩Consider the following algorithm which can be used for this language:

N= "On input where φ a Boolean formula in CNF"

Ifφ{ don't consists a unit clause} assume every literals.

Repetition performed until these exists no new (~x)unit clause:

If an empty clause is existing inrole="math" localid="1663228645556" φ reject.

Dependability can be viewed as:

Consider that CNF2∈P.

02

:Compare the CNF and P

Consider one more situation of ϕthat will be belonging to some other variable.

Consider another situation CNF3∈P.

Consider first situation of ϕand consider it belongs to some p and if there is anyp then reject. Consider one more situation of ϕthat will be belonging to some other variable, let's say qandr here situation will rejected if there is any-q otherwise accepted.

Similarly, this situation will be held true forCNFH∈P .

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