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If AmB and B is a regular language, does that imply that A is a regular language? Why or why not?

Short Answer

Expert verified

If AmB and B is a regular language, then that doesn鈥檛 implies that A is also regular language.

Step by step solution

01

Regular Language

Regular language is a language which can be accept by finite automata including deterministic and non-deterministic automata.

02

To check regularity of A

The statement, 鈥淚f AmBand B is a regular language, does that imply that A is a regular language?鈥 - is wrong. This is because the power of reduction function can be more the Deterministic Finite Automata (DFA).

For example, assume that there are two languages A={0n1n|forn0}and B=1, both are over the function =0,1.

Let there be a function as:

f(w)={1;ifwA0;ifwA

Now we can see, that A is Context Free language, thus it must be decidable. So, this makes f as computable function.

We also observe that wAif and only if fw=1, this is only true if fwB.

Therefore, AmB is regular language true but A is not regular language.

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