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A triangle in an undirected graph is a 3-clique. Show thatTRIANGLEP , where TRIANGLE=<G>|Gcontainsatriangle.

Short Answer

Expert verified

Three edges connection over based on the theory of polynomial show the length of inlet.

Step by step solution

01

To Turing Machine of Class-P

ClassP:Ps a class of languages that are decidable in polynomial time on a deterministic single 鈥 tape Turing 鈥 machine.

02

Undirected Graph of Clique

Specified language, a triangle is an undirected graph is a3-clique.Now we have to show that TRIANGLEP

Let AbetheTuringmachinethatdecidesTRIANGLE is polynomial timeAcan be described as follows:

:A=''oninputG<V,E>

V denotes set of vertices of the graph G.

Edenotes set of edges of the graphG.

For u,v,wVand u<v<wwe enumerate all triples<u,v,w>.Check whether all three edges u,v(v,w)exist in Eor not. If exist then accept.Otherwise reject.鈥

Enumeration of all triple require0(|v|3)time. Checking whether all three edges belong to E take 0(|E|)time.Overall time is 0(|V|3|E|)which is polynomial in the length of the inlets. Therefore TRIANGLEP. Three edges connection over base on the theory of polynomial showGthe length of inplet..

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