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91Ó°ÊÓ

Let itB be any language over the alphabet ∑. Prove that B=B+iffBB⊆B

Short Answer

Expert verified

Thus, the solution isx1,x2,x3∈B .

Step by step solution

01

Introduction

‘B’ is apply to any language over that alphabet∑.

To be confirmation about formula :-

B=B+iff BB⊆B

02

Explanation

One Direction: -


Assume: - B=B+ ----------- result (1)

To Show : -BB⊆B

Since, forevery language BB⊆B+ ------- result (2)

By Sabstitating (1) and (2) , it can be obtained that BB⊆B. Hence, it’s been confirmed that BB⊆B iff role="math" localid="1663234619808" BB=B+

Other Direction : -

Assume : - BB⊆B

To sure and confirmed : - -BB=B+

It’s in knowledge in every or any language BB⊆B+ --------- (3)

Let w be a string of elements, such that w∈B+w∈B.

If w∈B+than W the string can be divided within elements. x1,x2,x3,.....xksuchasw=x1,x2,x3....xkFor x1∈Bandk⩾1 .

After long duration x1x2∈Band it is assumed that BB∈B.

Same way, it hold for the different elements x3, as well as x3∈Band BB⊆B.Thus

x1,x2,x3∈B .

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