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$F_{DFA}$might establish that is a decidable language by building a Turing machine $\left(TM-1\right)$that would take tape input if it marked any accept state, but would reject it otherwise. To put it another way, a $DFA$on a truing machine will be simulated.

If both $DFAs$accept the same language, we can create a Turing machine that accepts a string if it belongs in one of the machines, but not both at the same time. We might achieve the end state by running $BFSorDFS$from the beginning. The time complexity is $O\left(\left|V\right|+\left|E\right|\right),$where$V$represents the number of states in a $DFAandE$represents the number of edges. We can observe which transitions were utilised once we discover the end state from the start state, and we can execute such a string on our Turing machine. This would take O(string-length), a polynomial time.

The resolution in time complexity using$BFSorDFS$$BFSorDFS$.