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Question: LetEREXI^

Short Answer

Expert verified

We know thatPSPACEEXSPACE i.e., the problem of any EXSPACE-complete cannot be in PSPACE.

Step by step solution

01

Using Regular expression with exponentiation

Consider the statementEREXI^={<R> R is regular expression with exponentiation and

L(R)=}

From the above statement it can be understood that R is a regular expression and the language, which contains this regular expression consists NULL values.

02

Applying the concept of intractability

EREXI^is said to be intractable because it can be demonstrated in such a manner that is complete for the class EXSPACE.

From the above statements we can conclude that 鈥渁ny EXSPACE-complete problem cannot be in PSPACE and it is much less in P鈥.

Because PSPACE will be same as EXSPACE which is contradicting the corollary discussed above.

Hence, it can be said thatEREXI^P

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