Chapter 2: Problem 6
Suppose that \(f: A \rightarrow B\) and \(g: B \rightarrow C\) are functions and that \(g \circ f\) is oneto-one. a) Prove that \(f\) is one-to-one. (Hint: use a proof by contradiction.) b) Find a specific example that shows that \(g\) is not necessarily one-to-one.
Short Answer
Expert verified
a) Yes, \(f\) must be one-to-one. b) No, \(g\) does not need to be one-to-one, as shown in the counterexample.
Step by step solution
01
Understanding the Problem
We know that the composition of two functions, \(g \circ f\), is one-to-one (injective), and we need to prove that the function \(f\) itself must be one-to-one. The second part of the task is to provide an example where \(g\) may not be one-to-one even though \(g \circ f\) is one-to-one.
02
Assume the Opposite
To prove by contradiction, assume that \(f\) is not one-to-one. This means there exists at least two distinct elements \(x_1, x_2 \in A\) such that \(f(x_1) = f(x_2)\), but \(x_1 eq x_2\).
03
Applying the Composition
Since \(f(x_1) = f(x_2)\), when we apply the function \(g\), we have \(g(f(x_1)) = g(f(x_2))\). This implies \((g \circ f)(x_1) = (g \circ f)(x_2)\).
04
Reaching a Contradiction
The function \(g \circ f\) is assumed to be one-to-one. Therefore, from \((g \circ f)(x_1) = (g \circ f)(x_2)\), it should follow that \(x_1 = x_2\). However, this contradicts our assumption that \(x_1 eq x_2\). Hence, our assumption that \(f\) is not one-to-one must be false. Consequently, \(f\) must be one-to-one.
05
Example for Part b: Construct Counterexample
Consider the function \(f: \{1, 2\} \rightarrow \{1, 2\}\) defined by \(f(x) = x\) and the function \(g: \{1, 2\} \rightarrow \{3\}\) defined by \(g(y) = 3\), a constant function. The composition \((g \circ f)(x) = 3\) is the same for any \(x\), so it's trivially injective. However, \(g(y) = 3\) for both 1 and 2, showing that \(g\) itself is not one-to-one.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-to-One Functions
One-to-one functions, also known as injective functions, are a crucial concept in mathematics. They have the special property that if any two different inputs are used, they will produce different outputs. In more formal terms, a function \( f: A \rightarrow B \) is considered one-to-one if, for all elements \( x_1, x_2 \in A \), \( f(x_1) = f(x_2) \) implies that \( x_1 = x_2 \).
This characteristic ensures a unique mapping from each element in the domain \( A \) to the codomain \( B \), making sure no two separate inputs can lead to the same output. One-to-one functions are essential in proving other mathematical properties and ensuring that each output corresponds to exactly one input, maintaining a precise relation between sets.
This characteristic ensures a unique mapping from each element in the domain \( A \) to the codomain \( B \), making sure no two separate inputs can lead to the same output. One-to-one functions are essential in proving other mathematical properties and ensuring that each output corresponds to exactly one input, maintaining a precise relation between sets.
Proof by Contradiction
Proof by contradiction is a powerful and logical method used to demonstrate the validity of a statement. The process involves assuming the opposite of what you want to prove and then showing that this assumption leads to a logical inconsistency.
Here's a clearer breakdown of the steps involved:
Here's a clearer breakdown of the steps involved:
- Assume the Opposite: Start by assuming that the statement you wish to prove is false.
- Show Inconsistencies: Work through the logical implications of this assumption until you find a contradiction—something that clearly cannot be true.
- Conclude the Original Statement: Since the assumption leads to a contradiction, the only logical conclusion is that the original statement must be true.
Injective Function
An injective function is another term for a one-to-one function, reinforcing the idea that no two different inputs produce the same output. In the context of the exercise given, we explored that if \( g \circ f \) is injective, it means the composition of functions remains one-to-one. Through the process, it can be proven that if the composition \( g \circ f \) is injective, \( f \) must also be injective to satisfy this property.
Key insights about injective functions include:
Key insights about injective functions include:
- Each element in the domain maps to a unique element in the codomain.
- Injective functions often play a critical role in ensuring the functionality of more complex mathematical operations, like function composition.
- Vital in various proofs and mathematical structures, injective functions maintain uniqueness and order within and among sets.
Counterexample
A counterexample is an example used to disprove a statement or hypothesis. In the exercise, a specific counterexample shows that even if the composed function \( g \circ f \) is one-to-one, it doesn't necessarily imply that \( g \) must be one-to-one. By using an example where \( f(x) = x \) and \( g(y) = 3 \), the function \( g \) is not one-to-one because it maps multiple y-values to the single value 3.
Counterexamples are crucial in mathematics because:
Counterexamples are crucial in mathematics because:
- They demonstrate the boundaries and conditions under which a statement holds true.
- They help in refining hypotheses and understanding nuances in mathematical logic.
- By identifying exceptions to rules, counterexamples are instrumental in teaching precision and critical thinking.