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Two pennies, a nickel, and a dime are placed in a cup. You draw a first coin and a second coin. a. Assuming you are sampling without replacement (that is, you don't replace the first coin before taking the second), write the sample space of all ordered pairs of letters \(\mathrm{P}, \mathrm{N}\), and \(\mathrm{D}\) that represent the outcomes. What would you say are the appropriate weights for the elements of the sample space? b. What is the probability of getting 11 cents?

Short Answer

Expert verified
The probability of getting 11 cents is \( \frac{2}{7} \).

Step by step solution

01

Understanding the Coins and Sample Space

We have a total of four coins: two pennies (P), one nickel (N), and one dime (D). The task is to pick two coins in succession and identify all possible sequences (ordered pairs) of these coins. Since we are sampling without replacement, each coin can only be selected once in each sample pair.
02

List Sample Space Pairs

To find the sample space, consider each possible pair where the first coin is selected and the second coin is selected from the remaining coins. The sample space is as follows: 1. PP (penny first, penny second) 2. PN (penny first, nickel second) 3. PD (penny first, dime second) 4. NP (nickel first, penny second) 5. ND (nickel first, dime second) 6. DP (dime first, penny second) 7. DN (dime first, nickel second)
03

Determine Weights for Sample Space

Each coin corresponds to two possibilities if chosen first because it can pair with any of the three remaining coins. However, we have repeated coins (pennies), so we need to adjust for this repetition. Given that there are more pennies, outcomes involving pennies may repeat more often. Upon balance: - PP occurs once, - Each of PN, PD, NP, ND, DP, DN occurs once. These yields equal probability for each pair.
04

Calculate Probability of Getting 11 Cents

To get 11 cents, you're looking for combinations involving a penny and a dime (PD or DP). From the sample space, PD and DP are both possibilities. Thus, there are 2 outcomes achieving 11 cents out of 7 total. Probability = Number of favorable outcomes / Total outcomes = 2/7.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
When dealing with discrete probability, the concept of "sample space" is foundational. It's the complete set of all possible outcomes of a particular experiment. In our exercise, where two coins are drawn from a cup containing two pennies, one nickel, and one dime, each possible pair of coins forms the sample space.

Since you are drawing coins without replacement, the possible outcomes change after the first draw. To list the sample space, we consider every coin being drawn in the first position and pairing it with a different remaining coin. This gives pairing options such as:
  • PP (penny first, penny second)
  • PN (penny first, then nickel)
  • PD (penny first, then dime)
  • NP (nickel first, then penny)
  • ND (nickel first, then dime)
  • DP (dime first, then penny)
  • DN (dime first, then nickel)
Each of these pairs is an element of the sample space, representing a unique outcome of choosing two coins in a specific order.
Probability Calculation
Probability calculation involves determining the likelihood of a given outcome in our sample space. This is usually expressed as a fraction, where the number of favorable outcomes is divided by the total number of outcomes.

In this exercise, we need to calculate the probability of drawing coins that total up to 11 cents. Since a penny is worth 1 cent and a dime is worth 10 cents, only the combinations PD (penny then dime) and DP (dime then penny) will sum up to 11 cents. From our sample space:
  • PD
  • DP
Thus, there are 2 favorable outcomes for drawing a total of 11 cents. Given there are 7 possible outcomes in total, the probability is calculated as:\[\text{Probability} = \frac{2}{7}\]
Combinatorics
Combinatorics is the branch of mathematics that deals with counting, arrangement, and combination of elements within a set. In the context of our exercise, combinatorics helps us systematically determine the possible outcomes of drawing coins.

When addressing the problem of choosing 2 coins in succession without replacement, we apply combinatorial principles. We start with 4 coins, and as each is chosen, the set reduces by one. Therefore, the order of choice matters, creating permutations of these choices.

The key is to ensure we consider every possible arrangement through permutation, taking into account that repetition of the same type of coin (in this case, the pennies) affects the outcome frequency. Understanding these fundamentals of combinatorics ensures that we accurately calculate probabilities and fully comprehend the array of possible events in the sample space.

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