Chapter 5: Problem 18
Prove as tight upper and lower bounds as you can for \(\sum_{i=1}^{k}(1 / i)\). For this purpose, it is useful to remember the definition of the natural logarithm as an integral involving \(1 / x\) and to draw rectangles and other geometric figures above and below the curve.
Short Answer
Expert verified
The bounds for \( S_k \) are \( \ln(k+1) < S_k < \ln(k) + 1 \).
Step by step solution
01
Identify the Task
The task is to find upper and lower bounds for the sum \( S_k = \sum_{i=1}^{k} \frac{1}{i} \).
02
Understanding Geometric Interpretation
To use geometric figures, consider the sum as the areas of rectangles with height \( \frac{1}{i} \) and width 1, from \( i = 1 \) to \( k \). These rectangles approximate the area under the curve \( y = \frac{1}{x} \).
03
Integral Representation
The natural logarithm can be expressed as an integral: \( \ln(k) = \int_{1}^{k} \frac{1}{x} \, dx \). This integral represents the area under the curve from 1 to \( k \).
04
Connecting Sum and Integral
Each rectangle's top-right corner touches the curve \( y=\frac{1}{x} \) at integer points. The sum \( S_k \) overestimates this integral since the top of each rectangle is above the area under the curve from \( x = i \) to \( x = i+1 \).
05
Establishing Upper Bound
Since \( S_k \) overestimates the integral \( \ln(k) \), we establish that \( S_k < \ln(k) + 1 \). The additional '1' accounts for the area of the rectangle between \( 0 \leq x < 1 \), as the starting point of the sum is actually \( i = 1 \).
06
Establishing Lower Bound
For a lower bound, consider the area under the curve from \( i = 1 \) to \( k \). This region is less than the sum of rectangle areas from 1 to \( k+1 \). Therefore, \( S_k > \ln(k+1) \), which excludes the area under the curve from \( k \) to \( k+1 \).
07
Combining Results
The bounds for the sum \( S_k \) can be combined: \( \ln(k+1) < S_k < \ln(k) + 1 \). These are tight bounds for \( S_k \) based on the integral approximation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is a mathematical function with a key relationship to calculus and analysis. In essence, it describes the area under the curve of \( y = \frac{1}{x} \) from 1 to \( x \). This integral form is expressed as:\[ \ln(k) = \int_{1}^{k} \frac{1}{x} \, dx \].
This integral representation is crucial for approximating sums and finding bounds, such as when analyzing the sum \( S_k = \sum_{i=1}^{k} \frac{1}{i} \). Natural logarithms are important because they allow us to understand growth rates in natural processes.
Key properties of \( \ln \):
This integral representation is crucial for approximating sums and finding bounds, such as when analyzing the sum \( S_k = \sum_{i=1}^{k} \frac{1}{i} \). Natural logarithms are important because they allow us to understand growth rates in natural processes.
Key properties of \( \ln \):
- \( \ln(1) = 0 \).
- It is undefined for non-positive values.
- It increases without bound as \( x \) grows.
- Its derivative, \( \frac{d}{dx}[ \ln(x) ] = \frac{1}{x} \), mirrors our function \( y = \frac{1}{x} \).
Integral Approximation
Integral approximation is a method used to estimate the area under a curve, often when a simple algebraic solution is not available. This technique is useful in deriving upper and lower bounds or finding approximate solutions to problems such as \( S_k = \sum_{i=1}^{k} \frac{1}{i} \).
By considering integrals, we can more accurately model areas using rectangles under a curve.
For instance, the expression:\[ \ln(k) = \int_{1}^{k} \frac{1}{x} \, dx \]
provides an approximation for the harmonic series sum. The following are some key points of integral approximation:
By considering integrals, we can more accurately model areas using rectangles under a curve.
For instance, the expression:\[ \ln(k) = \int_{1}^{k} \frac{1}{x} \, dx \]
provides an approximation for the harmonic series sum. The following are some key points of integral approximation:
- Upper Bound Approximation: When rectangular approximations overestimate the actual area, as in \( S_k < \ln(k) + 1 \).
- Lower Bound Approximation: When rectangular approximations underestimate the area under a curve, like \( \ln(k+1) \) for \( S_k \).
Geometric Interpretation
Geometric interpretation plays a significant role in visualizing mathematical concepts, particularly in calculus and approximation methods. When we examine the sum \( S_k = \sum_{i=1}^{k} \frac{1}{i} \), this approach helps us visualize the problem geometrically.
By plotting the function \( y = \frac{1}{x} \), we see that the sum can be thought of as a series of rectangles, each with height \( \frac{1}{i} \) over an interval of 1 unit width.
Here's the breakdown of the geometric interpretation:
By plotting the function \( y = \frac{1}{x} \), we see that the sum can be thought of as a series of rectangles, each with height \( \frac{1}{i} \) over an interval of 1 unit width.
Here's the breakdown of the geometric interpretation:
- Top-Right Corner Touch: Each rectangle's top-right corner touches the curve \( y = \frac{1}{x} \), meaning it approximates the area below it.
- Overestimation by Rectangles: Since these rectangles sit above the curve from \( x = i \) to \( x = i+1 \), they tend to overestimate the integral \( \int \frac{1}{x} \, dx \).
- Standout Areas: The starting area from 0 to 1 can be distinct, influencing bounds calculated for \( S_k \).