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Which is more likely, or are both equally likely? a. Drawing an ace and a king when you draw two cards from among the 13 spades, or drawing an ace and a king when you draw two cards from an ordinary deck of 52 playing cards? b. Drawing an ace and a king of the same suit when you draw two cards from a deck, or drawing an ace and a king when you draw two cards from among the 13 spades?

Short Answer

Expert verified
(a) Drawing from 13 spades is more likely. (b) Drawing from 13 spades is more likely.

Step by step solution

01

Understand the Problem

We are asked to compare the likelihood of two different card drawing scenarios, both separately for parts (a) and (b). Each involves drawing an ace and a king from a set of cards, but with different constraints.
02

Define the Events for Part (a)

For part (a), we will calculate and compare two probabilities: 1) Drawing an Ace and a King from only the 13 spades, and 2) Drawing an Ace and a King from an ordinary 52-card deck.
03

Probability from 13 Spades

In the 13 spades, there is one Ace and one King. To calculate the probability of drawing them, we first select the Ace (1/13), then the King (1/12), giving a total probability of drawing an Ace and a King: \( \frac{1}{13} \times \frac{1}{12} = \frac{1}{156} \).
04

Probability from 52-Card Deck

In a full deck, there are 4 Aces and 4 Kings. The probability of drawing an Ace first is \( \frac{4}{52} = \frac{1}{13} \), then a King is \( \frac{4}{51} \). Thus, the probability is: \( \frac{1}{13} \times \frac{4}{51} = \frac{4}{663} \).
05

Compare Probabilities for Part (a)

For the scenario with 13 spades: \( \frac{1}{156} \approx 0.0064 \). For the 52-card deck: \( \frac{4}{663} \approx 0.0060 \). Thus, drawing from the 13 spades is slightly more likely.
06

Define the Events for Part (b)

For part (b), we compare: 1) Drawing the Ace and King of the same suit from a full 52-card deck, and 2) Drawing an Ace and a King from only the 13 spades.
07

Calculating Same Suit from 52-Card Deck

For this event, first choose a suit (probability \( \frac{1}{4} \)). Then choose the Ace (1/13), and the King (1/12) in that suit: \( \frac{1}{4} \times \frac{1}{13} \times \frac{1}{12} = \frac{1}{624} \).
08

Compare Probabilities for Part (b)

For drawing from 13 spades, we have \( \frac{1}{78} \). For the 52-card deck \( \frac{1}{624} \approx 0.0016 \). The former is much higher, thus, drawing from 13 spades is more likely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
When we're working with problems involving drawing combinations of cards, we're engaging in the field of combinatorics. This branch of mathematics focuses on counting, arrangement, and combination of elements within sets. For card games, the concept is particularly important since we often need to determine the number of possible outcomes or favorable arrangements in a given situation.
In our exercise, we are faced with two main scenarios: drawing specific combinations from a subset of 13 spades, and drawing combinations from the entire 52-card deck. To solve these, we have to consider combinations without replacement, which means once a card is drawn, it cannot be drawn again from the same set.
By calculating the probability of drawing two specific cards, such as an ace and a king, we must determine all possible arrangements that include these cards. The formulation \( \frac{1}{n} \times \frac{1}{n-1} \) is used to calculate the probability of specific sequences of draws, like selecting an ace followed by a king from the spades shown in the exercise, using basic counting principles.
Basic Probability
At its core, probability quantifies the chance of an event happening. In card games, this translates into finding how likely it is to draw certain cards from a deck. Knowing probabilities helps in making informed decisions during gameplay by evaluating the best strategy based on potential outcomes.
The probability of drawing an ace and then a king from any subset of our deck can be express in terms of the ratio of favorable outcomes to the total number of ways to draw two cards. In our solution, we calculated probabilities for drawing these combinations from different sets. For instance, with 13 spades: \( \frac{1}{13} \times \frac{1}{12} = \frac{1}{156} \). For the full deck: \( \frac{4}{52} \times \frac{4}{51} = \frac{4}{663} \). These fractions simplify computing the likelihood of an event happening.
Therefore, understanding basic probability helps us predict outcomes based on established rules of drawing, affecting our decisions and strategies.
Card Suit Probabilities
Another aspect worth understanding is how card suits affect probability. In a regular deck, there are four suits: hearts, diamonds, clubs, and spades. Each suit consists of 13 unique cards, which impacts the probability calculations when dealing with single suits versus the entire deck.
In problem (b) of our exercise, we compared drawing an ace and a king of the same suit versus drawing these cards from only the spades. When restricted to one suit in a full deck, the probability involves choosing a suit \( \frac{1}{4} \), then specific cards within that suit: \( \frac{1}{13} \times \frac{1}{12} \). This evaluation \( \frac{1}{624} \) mirrors the restrictive nature of probabilities because suits have a fixed number of specific cards.
The exploration of suit probabilities demonstrates how restrictions in card options shift the likelihood of certain outcomes. It highlights the importance of knowing details of card suits to accurately evaluate chances in various card game scenarios.

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