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Compute the variance \(\operatorname{Var}(X)\) of the random variable \(X\) that counts the number of heads in four flips of a coin that lands heads with a frequency of \(1 / 3 .\)

Short Answer

Expert verified
The variance \(\operatorname{Var}(X)\) is \(\frac{8}{9}\).

Step by step solution

01

Understand the Random Variable

The random variable \(X\) represents the number of heads observed in 4 flips of a biased coin, where the probability \(p\) of getting a head is \(\frac{1}{3}\) and the probability \(q = 1 - p = \frac{2}{3}\) of getting a tail.
02

Recognize the Distribution Type

Since we are flipping a coin 4 times and counting the number of heads, \(X\) follows a binomial distribution with parameters \(n = 4\) (the number of trials) and \(p = \frac{1}{3}\) (the probability of success on each trial).
03

Recall the Variance Formula for Binomial Distribution

For a binomial distribution \(X \sim \text{Binomial}(n, p)\), the variance \(\operatorname{Var}(X)\) is given by \(npq\), where \(q = 1 - p\).
04

Calculate the Variance

Using the formula \(\operatorname{Var}(X) = npq\), substitute \(n = 4\), \(p = \frac{1}{3}\), and \(q = \frac{2}{3}\): \[ \operatorname{Var}(X) = 4 \times \frac{1}{3} \times \frac{2}{3} = \frac{8}{9} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance
Variance is a measure that tells us how much the values of a random variable are spread out. In simpler terms, it provides an idea of how much the outcomes vary from the expected average. When rolling a die or flipping a coin, the variance helps to quantify the unpredictability of these events.

For a binomial distribution, which deals with a fixed number of independent trials of a binary outcome (like flipping a coin), the formula for variance is \(npq\). In this context:
  • \(n\) is the number of trials
  • \(p\) is the probability of success (such as getting a head)
  • \(q = 1 - p\) is the probability of failure (like getting a tail)

For our exercise, where four coin flips are involved and the coin lands heads with a frequency of \(\frac{1}{3}\), the variance is calculated using the formula: \[ \operatorname{Var}(X) = npq = 4 \times \frac{1}{3} \times \frac{2}{3} = \frac{8}{9} \]This result tells us how much the number of observed heads might fluctuate from the average or expected values when the coin is flipped four times.
Random Variable
A random variable is a mathematical construct used to quantify outcomes of a random phenomenon. It's a convenient way to model situations with uncertain results in a manageable mathematical framework.

For example, when flipping a coin, the outcome can be a head or a tail. Here, our random variable \(X\) counts the number of heads in four flips of a biased coin.

Since each flip is an independent event, meaning the outcome of one flip does not affect the others, we define \(X\) to take values within a specific range based on given probabilities:
  • 0 heads: All flips result in tails
  • 1 head: 1 out of 4 flips result in a head
  • 2 heads: 2 out of 4 flips result in heads
  • 3 heads: 3 out of 4 flips result in heads
  • 4 heads: All flips result in heads

This variable, \(X\), follows a binomial distribution as it involves multiple trials with two possible results (head or tail) in each trial. Modeling problems like this helps predict the likelihood of various outcomes, which is especially useful in fields like statistics and probability.
Probability
Probability measures how likely an event is to occur. It's a way of quantifying uncertainty. In the context of our exercise, probability helps us determine the likelihood of observing a specific number of heads when flipping a biased coin.

The biased coin means that the outcomes (head or tail) do not have an equal chance of occurring. In our example:
  • The probability \(p\) of flipping a head is \(\frac{1}{3}\)
  • The probability \(q = 1 - p\) of flipping a tail is \(\frac{2}{3}\)

These probabilities allow us to predict the expected outcomes over multiple coin flips. When using binomial distribution in probability:
  • Each flip is a trial.
  • Each trial has a binary outcome — success (head) or failure (tail).
  • We seek to find out the probability of getting 0 to 4 heads in four flips.

Understanding these basic principles enables to better model and predict various outcomes, making the study of probability essential in both theoretical and practical applications.

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Most popular questions from this chapter

Two nickels and a dime are shaken together and thrown. All the coins are fair. We are allowed to keep the coins that turn up heads. Give two sample spaces together with probability density functions that reasonably describe this situation. Explain your answer.

Suppose we draw three balls from an urn containing two red balls and three black balls. We do not replace the balls after we draw them. In terms of the hypergeometric distribution, what is the probability of getting two red balls? Compute this probability.

A fair coin is tossed five times. Determine the probability that: (a) It turns up tails every time. (b) It turns up heads at most three times. (c) It turns up heads twice in a row exactly one time.

A television show features the following weekly game: A sports car is hidden behind one door, and a goat is hidden behind each of two other doors. The moderator of the show invites the contestant to pick a door at random. Then, by tradition, the moderator is obligated to open one of the two doors not chosen to reveal a goat (there are two goats, so there is always such a door to open). At this point, the contestant is given the opportunity to stand pat (do nothing) or to choose the remaining door. Suppose you are the contestant, and suppose you prefer the sports car over a goat as your prize. What do you do? (Hint: It may help to model this as a two-stage dependent trials process, but it may not be obvious how to do this). (a) Suppose you decide to stand with your original choice. What are your chances of winning the car? (b) Suppose you decide to switch to the remaining door. What are your chances of winning the car? (c) Suppose you decide to flip a fair coin. If it comes up heads, you change your choice; otherwise, you stand pat. What are your chances of winning the car?

Compute the variance \(\operatorname{Var}(X)\) of the random variable \(X\) that counts the number of heads in four flips of a fair coin.

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