/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Expand \((a+b+c)^{2}\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Expand \((a+b+c)^{2}\)

Short Answer

Expert verified
The expanded expression is \(a^{2} + b^{2} + c^{2} + 2ab + 2bc + 2ca\).

Step by step solution

01

Identify the Expression

The expression we need to expand is \[(a+b+c)^{2}\]This is a binomial expression, and it needs to be expanded using the distributive property or a known algebraic identity.
02

Use the Expansion Formula

Use the formula for expanding a squared trinomial: \[(a+b+c)^{2} = a^{2} + b^{2} + c^{2} + 2ab + 2bc + 2ca\]This formula will guide the expansion process.
03

Apply the Formula to Each Term

Apply the formula step-by-step:- First, square each term: - \(a^{2}\) - \(b^{2}\) - \(c^{2}\)- Next, find each pairwise product and multiply by 2: - \(2ab\) - \(2bc\) - \(2ca\)
04

Write the Expanded Expression

Combine all terms obtained in the previous step. The expanded form of the expression is:\[a^{2} + b^{2} + c^{2} + 2ab + 2bc + 2ca\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distributive Property
In algebra, the distributive property is a key principle that helps us manage expressions involving multiplication and addition. This property allows us to break down complex expressions into more manageable pieces, especially when expanding or simplifying algebraic expressions. It states that for any numbers or expressions, you distribute the multiplication over addition:
  • \(a(b + c) = ab + ac\)
This means you can multiply each part of the expression inside the parentheses by the term outside. This property is particularly helpful when dealing with expressions like \((a + b + c)^2\), where each term in the binomial needs to be squared and each pair of terms multiplied together. Applying the distributive property efficiently can simplify complex polynomial expansions and is an essential skill in algebra.
Algebraic Identity
Algebraic identities are special equations that hold true for all values of the variables included. They provide formulas or rules, helping to simplify algebraic expressions. One of the most common identities is the formula for the square of a trinomial, such as \((a + b + c)^2\). This identity can be written as:
  • \[(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca\]
This is more than just a formula—it's a powerful tool to expand expressions systematically. By applying this identity, you eliminate guesswork and can quickly expand any squared trinomial. Understanding and using algebraic identities effectively helps you solve problems faster and more accurately, as shown in this exercise.
Squared Trinomial
The concept of a squared trinomial involves taking a trinomial expression—one with three terms—and squaring it. This operation creates a polynomial with specific characteristics. The expression \((a + b + c)\) represents a trinomial, and squaring it involves expanding it using a known formula:
  • \((a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca\)
A squared trinomial results in nine distinct operations: three squaring operations for each term, and six multiplication operations for each pair of terms, each summed up with a factor of two due to their symmetry. Understanding such structures and the resulting polynomial can help you solve and expand trinomials efficiently. Using these strategies makes complex algebraic expressions simpler to manage and lays the foundation for more advanced problem-solving in algebra.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that there are \(\left(3^{n}+1\right) / 2\) strings of length \(n\) consisting of the letters \(a, b\), and \(x\) in which \(a\) occurs an even number of times.

How many ways can 12 black pawns be placed on the black squares of an \(8 \times 8\) chess board? How many ways can 12 black pawns and 12 white pawns be placed on the black squares of an \(8 \times 8\) chess board? Half the 64 squares are black and half are red. No black (red) square shares an edge with a black (red) square.

The English alphabet contains 26 letters, including five vowels. In each case determine how many words of length five are possible provided that: (a) Words contain at most two distinct vowels (b) Words contain at most one letter that is a vowel (c) Words contain at least four distinct vowels

A series of articles about 26 athletic teams will appear over 26 consecutive weeks. How many ways can the articles be ordered? What if the first week's article must be about the current champion? What if team \(A\) and team \(B\) must be featured in consecutive weeks?

Internet Addresses: IPv4 and IPv6. The Internet requires an address for each machine that is connected to it. The address space of the addressing architecture of Internet Protocol version 4 (IPv4) consists of a 32 -bit field. Since not every combination of bits can be used as an address, plans are underway to change the address space to a 128 -bit field in IPv6. The 32 -bit IPv4 addresses are usually written in a form called dotted decimal. The 32 bit address is broken up into four 8 -bit bytes, and these bytes are then converted to their equivalent decimal form and separated by dots. For example. $$ \begin{array}{ll} 1000000000000011 & 00000010000000011 \end{array} $$ is written as 128.3 .2 .3 , which is obviously more readable. The 128 -bit IPv6 addresses are divided into eight 16 -bit pieces. Each 16 -bit piece is converted to its equivalent hexadecimal value (each sequence of 4 bits is converted to one hexadecimal digit). The eight four-character hexadecimal strings are separated by colons. It is not prac. tical to list 128 bits and show the conversion to the final IPv6 address form. As an example of what you might end up with, however, we show one IPv6 address: \(\mathrm{FFDC} \cdot \mathrm{BA} 98: 7654 \cdot 3210: \mathrm{FEDC}: \mathrm{BA} 98: 7654 \cdot 3210\) How many IPv4 addresses are possible?

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.