/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A disadvantage of a broadcast su... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A disadvantage of a broadcast subnet is the capacity wasted when multiple hosts attempt to access the channel at the same time. As a simplistic example, suppose that time is divided into discrete slots, with each of the \(n\) hosts attempting to use the channel with probability \(p\) during each slot. What fraction of the slots will be wasted due to collisions?

Short Answer

Expert verified
Fraction wasted due to collisions: \[1 - n imes p imes (1-p)^{n-1}\].

Step by step solution

01

Define Slot Collision

In a network with multiple hosts, a collision occurs in a time slot if two or more hosts attempt to use the channel simultaneously. Our goal is to find the probability of such an event.
02

Calculate the No Collision Probability

For there to be no collision in a time slot, exactly one host must attempt to use the channel, while all others do not. The probability that a specific host does not attempt to use the channel is q = 1-p . Thus, the probability that a specific host uses the channel is p , and all other (n-1) hosts do not is given by p imes q^{n-1} .
03

Calculate Non-collision for Any Host

Since any one of the n hosts can occupy the channel without collision, we add up the probabilities for each host. Thus, the probability that exactly one host uses the channel is n imes p imes q^{n-1} .
04

Calculate Collision Probability

The probability that a time slot experiences a collision (i.e., is wasted) is the complement of the probability that exactly one host uses the channel. This is given by:\[1 - n imes p imes q^{n-1}\]
05

Simplify the Expression

Substituting q = 1-p into the expression for collision probability, we get:\[1 - n imes p imes (1-p)^{n-1}\]. This expression represents the fraction of time slots that will be wasted due to collisions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Network Collision
Network collisions occur when multiple hosts in a network try to communicate simultaneously over the same channel. Imagine a bustling playground where many children want to use the same swing set. If two or more children jump onto the swing at the same time, they might collide, causing a disruption. Similarly, in a network, when two or more hosts try to use the same communication channel at the same instant, a collision happens.

The challenge with network collisions is that they can significantly reduce the efficiency of the network. Each failed attempt where data collides requires a retransmission, consuming even more bandwidth. As the number of hosts increases, so does the potential for collisions, making it crucial to find ways to minimize them.

The scenario we're looking at involves hosts accessing a channel during predefined time slots. If no collision management is in place, the data might clash, requiring all the involved parties to wait, retry, and use up the time slots inefficiently.
Channel Access Probability
Channel access probability is crucial in understanding how often hosts attempt to communicate over a shared channel. Consider this probability like the chance of a child deciding to use the swing in our playground analogy. Each time slot represents an opportunity for one or more hosts to access the channel and try to send data.

The probability with which each host attempts to use the channel in these time slots is denoted by the variable \(p\). When a host tries to access the channel during a particular time slot, it means there's a chance for data to be sent. If this access probability, \(p\), is too high, the likelihood of collisions increases because more hosts will end up trying to communicate at the same time. Conversely, if \(p\) is too low, the channel might remain underutilized, and network efficiency could suffer due to too many idle slots.

To achieve a balance, network design often involves tweaking this probability so that the network can support as many hosts as possible with minimal collisions. The careful adjustment of \(p\) helps maintain a network's overall efficiency and reliability.
Slot Waste Calculation
Slot waste occurs when the valuable time allocated for data transmission is rendered ineffective due to collisions. To calculate how much of this time is indeed wasted, it's essential to comprehend the collision probability.

Given \(n\), the number of hosts, and \(p\), the probability of any particular host accessing the channel at a time slot, we can calculate how frequently time slots get wasted. The key is to subtract the probability of exactly one host accessing the channel without collisions from the total probability of time slots being used.

The formula \[1 - n \times p \times (1-p)^{n-1}\] gives us the fraction of time slots wasted due to network collisions. Here, \((1-p)^{n-1}\) is the probability that all the other hosts do not access the channel in that given slot, making it crucial for finding when the collisions do not occur. By calculating this, users can understand how often resources are being wasted due to mismanaged channel access, providing data for improving network protocols and reducing inefficiencies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How long was a bit in the original \(802.3\) standard in meters? Use a transmission speed of \(10 \mathrm{Mbps}\) and assume the propagation speed of the signal in coax is \(2 / 3\) the speed of light in vacuum.

Ethernet and wireless networks have some similarities and some differences. One property of Ethernet is that only one frame at a time can be transmitted on an Ethernet. Does \(802.11\) share this property with Ethernet? Discuss your answer.

Write a program that implements message flow from the top layer to the bottom layer of the 7-layer protocol model. Your program should include a separate protocol function for each layer. Protocol headers are sequence up to 64 characters. Each protocol function has two parameters: a message passed from the higher layer protocol (a char buffer) and the size of the message. This function attaches its header in front of the message, prints the new message on the standard output, and then invokes the protocol function of the lower- layer protocol. Program input is an application message.

A group of \(2^{n}-1\) routers are interconnected in a centralized binary tree, with a router at each tree node. Router \(i\) communicates with router \(j\) by sending a message to the root of the tree. The root then sends the message back down to \(j\). Derive an approximate expression for the mean number of hops per message for large \(n\), assuming that all router pairs are equally likely.

Provide a list of reasons for why the response time of a client may be larger than the best-case delay.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.