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91Ó°ÊÓ

Read the man page (or Windows equivalent) for the Unix/Windows utility netstat. Use netstat to see the state of the local TCP connections. Find out how long closing connections spend in TIME_WAIT.

Short Answer

Expert verified
Use `netstat -an` to see TCP connections. Check netstat documentation for TIME_WAIT duration, typically around 60 seconds.

Step by step solution

01

- Open Command Prompt/Terminal

On your computer, open the Command Prompt (Windows) or Terminal (Unix/Linux).
02

- Run netstat Command

Type the command `netstat -an` and press Enter. This command will display all current TCP connections and listening ports.
03

- Identify TCP Connections in TIME_WAIT

Look through the list of connections, specifically focusing on those in the TIME_WAIT state. Connections in this state are waiting to be fully closed.
04

- Check TIME_WAIT Duration in Documentation

Check the man page (on Unix/Linux, use `man netstat`) or online documentation for netstat to find how long connections remain in TIME_WAIT. Typically, this duration is defined by the TCP/IP protocol specifications and can be around 60 seconds on most systems.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

TCP connections monitoring
To effectively manage and troubleshoot network issues, it's crucial to monitor TCP connections. TCP, or Transmission Control Protocol, is responsible for ensuring reliable communication between devices over a network. Keeping an eye on these connections helps in understanding the status and performance of your network.
One way to do this is by using the netstat command. This tool can display all active connections and listening ports, providing a snapshot of your network activity.
By monitoring TCP connections, you can:
  • Identify open, closed, or problematic connections.
  • Understand traffic loads and potential bottlenecks.
  • Ensure network security by checking for unauthorized connections.
Regular monitoring helps in maintaining an optimal and secure network environment.
netstat command
Netstat is a command-line utility that provides network statistics, including details on current TCP connections. It's available on both Unix/Linux and Windows systems.
To use netstat, open your Command Prompt (Windows) or Terminal (Unix/Linux). Then, run the command `netstat -an`. This command will list all current TCP connections and listening ports, along with their states.
The information displayed includes:
  • Local address and port number.
  • Foreign address and port number.
  • State of the connection (e.g., ESTABLISHED, TIME_WAIT).
Netstat is invaluable for network troubleshooting, enabling you to quickly assess connection statuses and performance.
TIME_WAIT state
When monitoring TCP connections with netstat, you'll often encounter connections in the TIME_WAIT state. This state indicates that a connection has been closed, but the protocol is ensuring all data has been transmitted properly before freeing up resources.
Connections in TIME_WAIT stay there for a specific duration, typically around 60 seconds, as defined by the TCP/IP protocol.
Understanding the TIME_WAIT state is essential because it:
  • Prevents old duplicate segments from being interpreted as part of a new connection.
  • Ensures the remote connection has received the acknowledgment of connection termination.
To find out how long connections remain in TIME_WAIT, consult the man page for netstat (type `man netstat` in Unix/Linux Terminal) or online documentation. Properly managing TIME_WAIT connections can improve network efficiency and resource utilization.

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Most popular questions from this chapter

Suppose TCP operates over a 1-Gbps link. (a) Assuming TCP could utilize the full bandwidth continuously, how long would it take the sequence numbers to wrap around completely? (b) Suppose an added 32-bit timestamp field increments 1000 times during the wraparound time you found above. How long would it take for the timestamp to wrap around?

One of the purposes of TIME_WAIT is to handle the case of a data packet from a first incarnation of a connection arriving very late and being accepted as data for the second incarnation. (a) Explain why, for this to happen (in the absence of TIME_WAIT), the hosts involved would have to exchange several packets in sequence after the delayed packet was sent but before it was delivered. (b) Propose a network scenario that might account for such a late delivery.

Suppose BLAST runs over a 10-Mbps Ethernet, sending \(32 \mathrm{~K}\) messages. (a) If the Ethernet packets can hold 1500 bytes of data, and optionless IP headers are used as well as BLAST headers, how many Ethernet packets are required per message? (b) Calculate the delay due to sending a \(32 \mathrm{~K}\) message over Ethernet (i) directly (ii) broken into pieces as in (a), with one bridge Ignore propagation delays, headers, collisions, and interpacket gaps.

If a UDP datagram is sent from host \(\mathrm{A}\), port \(\mathrm{P}\) to host \(\mathrm{B}\), port \(\mathrm{Q}\), but at host \(\mathrm{B}\) there is no process listening to port \(Q\), then \(B\) is to send back an ICMP Port Unreachable message to A. Like all ICMP messages, this is addressed to A as a whole, not to port \(\mathrm{P}\) on \(\mathrm{A}\). (a) Give an example of when an application might want to receive such ICMP messages. (b) Find out what an application has to do, on the operating system of your choice, to receive such messages. (c) Why might it not be a good idea to send such messages directly back to the originating port \(\mathrm{P}\) on \(\mathrm{A}\) ?

Consider a simple UDP-based protocol for requesting files (based somewhat loosely on the Trivial File Transport Protocol, TFTP). The client sends an initial file request, and the server answers (if the file can be sent) with the first data packet. Client and server then continue with a stop-and-wait transmission mechanism. (a) Describe a scenario by which a client might request one file but get another; you may allow the client application to exit abruptly and be restarted with the same port. (b) Propose a change in the protocol that will make this situation much less likely.

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