/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 True or false? a. Host \(A\) i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

True or false? a. Host \(A\) is sending Host \(B\) a large file over a TCP connection. Assume Host B has no data to send Host A. Host B will not send acknowledgments to Host A because Host B cannot piggyback the acknowledgments on data. True or false? a. Host \(\mathrm{A}\) is sending Host \(\mathrm{B}\) a large file over a \(\mathrm{TCP}\) connection. Assume Host B has no data to send Host A. Host B will not send acknowledgments to Host A because Host B cannot piggyback the acknowledgments on data. b. The size of the TCP rwnd never changes throughout the duration of the connection. c. Suppose Host A is sending Host B a large file over a TCP connection. The number of unacknowledged bytes that A sends cannot exceed the size of the receive buffer. d. Suppose Host \(\mathrm{A}\) is sending a large file to Host \(\mathrm{B}\) over a TCP connection. If the sequence number for a segment of this connection is \(m\), then the sequence number for the subsequent segment will necessarily be \(m+1\). e. The TCP segment has a field in its header for rwnd. f. Suppose that the last SampleRTT in a TCP connection is equal to \(1 \mathrm{sec}\). The current value of TimeoutInterval for the connection will necessarily be \(\geq 1 \mathrm{sec}\). g. Suppose Host A sends one segment with sequence number 38 and 4 bytes of data over a TCP connection to Host B. In this same segment the acknowledgment number is necessarily 42 .

Short Answer

Expert verified
a. False; b. False; c. True; d. False; e. True; f. False; g. True.

Step by step solution

01

Understanding the TCP Acknowledgments

In statement a, we need to decide whether Host B will send acknowledgments even if it has no data to send back to Host A. In a TCP connection, acknowledgments are crucial for ensuring data is correctly received, and they are sent regardless of whether Host B has data to send back. Piggybacking on data is optional but not required for sending acknowledgments. Thus, Host B will send acknowledgments independently of having data to piggyback on.
02

TCP Receive Window Size

For statement b, the concern is about the TCP receive window (rwnd) size changing. The receive window is dynamic and can change throughout the session to accommodate varying network conditions, like changes in available buffer space. Therefore, stating that the rwnd never changes during the connection is false.
03

Maximum Unacknowledged Bytes in TCP

In statement c, the report is on how many unacknowledged bytes Host A can send. TCP ensures data transfer within limits specified by the receiver's buffer size to prevent overflow, meaning the number of unacknowledged bytes should not exceed the receive buffer size. Therefore, this statement is true.
04

TCP Sequence Numbers

Statement d revolves around TCP sequence numbers. TCP sequence numbers increase by the number of bytes transmitted, not merely by one. Consequently, if a segment with sequence number \(m\) contains several bytes, the next sequence number will reflect the total number of bytes from \(m\), not \(m+1\). This statement is false.
05

TCP Header Fields

In statement e, the TCP header includes several fields, including ones for flow control such as the receive window (rwnd). Therefore, it is true that TCP has a header field for rwnd.
06

TCP Timeout Interval Calculation

For statement f, relating to the TimeoutInterval, it adapts based on network conditions and the computed EstimateRTT. While the last SampleRTT is equal to 1 second, the TimeoutInterval can be greater, as it typically accounts for variability and network delay factors. However, it isn't "necessarily" \(\geq 1\) sec, since parameters such as DevRTT can influence it to potentially be less.
07

TCP Acknowledgment Number Calculation

Finally, statement g discusses the acknowledgment number if Host A sends 4 bytes starting from sequence number 38. The acknowledgment number should be the cumulative acknowledgment of the next expected byte, which should be 38 + 4, that is 42. Thus, the statement is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

TCP Acknowledgments
In a TCP connection, acknowledgments are vital for ensuring data integrity and reliability. Host B will send acknowledgments back to Host A even if Host B has no data to transmit. This process is independent of piggybacking, which is the practice of sending acknowledgment packets alongside data packets to optimize network usage. Piggybacking is optional; acknowledgments in a TCP connection are mandatory and operate continuously to inform the sender about successfully received packets. This mechanism ensures continuous communication and error detection, allowing retransmissions when necessary.
TCP Receive Window
The TCP receive window (rwnd) is a crucial part of flow control, dictating how much data the receiver can process at any given time. It is dynamic and adjusts in response to network conditions, such as buffer availability and network congestion. This adjustment occurs to ensure efficient data flow and prevent loss by adapting to current transmission capabilities. Because of this adaptability, the statement that the size of the TCP receive window never changes is false. Understanding rwnd helps in managing throughput and avoiding data overflow on the receiving end.
TCP Sequence Numbers
TCP sequence numbers are used to keep track of the bytes during transmission. Unlike some assumptions, TCP sequence numbers do not merely increase by one for each segment sent. Instead, the sequence number reflects the number of bytes transmitted, increasing accordingly. For example, if a segment starts with sequence number \( m \) and contains several bytes, the subsequent sequence number will reflect this total, not simply \( m + 1 \). This mechanism is part of TCP's design to ensure orderly and accurate data transmission, helping the receiver properly reconstruct the message.
TCP Header Fields
The TCP header encompasses various fields critical for connection management, including the receive window (rwnd). These fields provide essential parameters for synchronization, data flow control, and reliability. The rwnd field within the header helps manage data flow by informing the sender about the available buffer space, allowing the sender to adjust the data flow rate appropriately. This flow control is vital for maintaining efficient communication and preventing data loss due to buffer overflow. The presence of specific fields like rwnd in the TCP header illustrates the protocol's comprehensive design for managing diverse network conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In our rdt protocols, why did we need to introduce sequence numbers?

Consider two network entities, \(\mathrm{A}\) and \(\mathrm{B}\), which are connected by a perfect bidirectional channel (i.e., any message sent will be received correctly; the channel will not corrupt, lose, or re-order packets). A and B are to deliver data messages to each other in an alternating manner: First, A must deliver a message to \(\mathrm{B}\), then \(\mathrm{B}\) must deliver a message to \(\mathrm{A}\), then \(\mathrm{A}\) must deliver a message to \(\mathrm{B}\) and so on. If an entity is in a state where it should not attempt to deliver a message to the other side, and there is an event like rdt_send (data) call from above that attempts to pass data down for transmission to the other side, this call from above can simply be ignored with a call to rdt_unable_to_send (data), which informs the higher layer that it is currently not able to send data. [Note: This simplifying assumption is made so you don't have to worry about buffering data.] Draw a FSM specification for this protocol (one FSM for A, and one FSM for B!). Note that you do not have to worry about a reliability mechanism here; the main point of this question is to create a FSM specification that reflects the synchronized behavior of the two entities. You should use the following events and actions that have the same meaning as protocol rdt \(1.0\) in Figure 3.9: rdt_send(data), packet = make_pkt(data), udt_send (packet), rdt_rcv (packet), extract (packet, data), deliver_data (data). Make sure your protocol reflects the strict alternation of sending between \(\mathrm{A}\) and \(\mathrm{B}\). Also, make sure to indicate the initial states for A and B in your FSM descriptions.

True or false? Consider congestion control in TCP. When the timer expires at the sender, the value of ssthresh is set to one half of its previous value.

Consider that only a single TCP (Reno) connection uses one \(10 \mathrm{Mbps}\) link which does not buffer any data. Suppose that this link is the only congested link between the sending and receiving hosts. Assume that the TCP sender has a huge file to send to the receiver, and the receiver's receive buffer is much larger than the congestion window. We also make the following assumptions: each TCP segment size is 1,500 bytes; the two-way propagation delay of this connection is \(150 \mathrm{msec}\); and this TCP connection is always in congestion avoidance phase, that is, ignore slow start. a. What is the maximum window size (in segments) that this TCP connection can achieve? b. What is the average window size (in segments) and average throughput (in bps) of this TCP connection? c. How long would it take for this TCP connection to reach its maximum window again after recovering from a packet loss?

Recall the macroscopic description of TCP throughput. In the period of time from when the connection's rate varies from \(W /(2 \cdot R T T)\) to \(W / R T T\), only one packet is lost (at the very end of the period). a. Show that the loss rate (fraction of packets lost) is equal to $$ L=\text { loss rate }=\frac{1}{\frac{3}{8} W^{2}+\frac{3}{4} W} $$ b. Use the result above to show that if a connection has loss rate \(L\), then its average rate is approximately given by $$ =\frac{1.22 \cdot M S S}{R T T \sqrt{L}} $$

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.