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Consider sending a packet from a source host to a destination host over a fixed route. List the delay components in the end-to-end delay. Which of these delays are constant and which are variable?

Short Answer

Expert verified
Processing, transmission, and propagation delays are constant; queuing delay is variable.

Step by step solution

01

Identify the Delay Components

The end-to-end delay in packet transmission is composed of four main delay components: processing delay, queuing delay, transmission delay, and propagation delay. Each of these components contributes to the total time taken for a packet to travel from the source to the destination.
02

Explain Processing Delay

Processing delay is the time a router takes to examine the packet's header and determine where to direct the packet. This delay is usually a fixed or constant delay because it relies on the capabilities of the router and does not change frequently under normal conditions.
03

Explain Queuing Delay

Queuing delay refers to the time a packet spends waiting in queue before it can be transmitted. This delay is variable as it depends on the network congestion and can change with the traffic load on the network.
04

Explain Transmission Delay

Transmission delay is the time required to push all the packet's bits onto the wire. It is calculated as the packet's length divided by the transmission rate of the link. This is generally constant for a given packet size and link speed.
05

Explain Propagation Delay

Propagation delay is the time it takes for a signal to travel from the sender to the receiver through the medium (like a copper wire or fiber optic cable). This is determined by the distance and speed of the signal in the medium and is considered a constant delay.
06

Summarize Constant and Variable Delays

In summary, processing, transmission, and propagation delays are constant delays in the context of a fixed route and consistent network conditions, while queuing delay is variable due to its dependence on network traffic conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Processing Delay
When a packet is sent from one host to another, it encounters a range of processes at each router it passes through. Processing delay is the time taken by a router to actually analyze the incoming packet's header. This involves examining routing information, checking for errors, and deciding the next hop for the packet's journey. Since routers have a consistent speed of internal processing, the processing delay is considered constant. Thus, once a route is set, this delay remains the same for every packet unless there's a hardware change or failure.
Exploring Queuing Delay
Queuing delay occurs when packets have to wait before they can be transmitted due to congestion on a network link. This is a bit like waiting in a line at a busy coffee shop. If the network is crowded with packets, each one has to wait its turn. Unlike processing and other delays, queuing delay is highly variable. Factors that influence it include the traffic load on the network and the current condition of the queue.
More traffic typically means longer queues, leading to increased delays. Because of this variability, queuing delay can be unpredictable, often leading to differences in total end-to-end delay.
Transmission Delay Essentials
Transmission delay is essentially how long it takes for a router to put all packet bits onto the transmission medium. It's calculated based on the packet's length and the rate at which bits are transmitted (the link's data rate).
This delay is usually constant for a given packet size and network link, assuming consistent conditions. For instance, on a 1 Gbps link with a packet of 1,500 bytes, the transmission delay would be approximately \[ \text{Transmission Delay} = \frac{1500 \times 8}{1,000,000,000} \approx 0.012 \text{ milliseconds} \]. Such predictability makes it a reliable component for understanding the end-to-end delay.
Delving into Propagation Delay
Propagation delay is the time it takes for a signal to travel from the source to the destination's physical medium. This spans across the entire length of the transmission path. The main factors influencing this delay are the distance the signal must travel and the speed at which it propagates through the medium (like fiber optics or copper cables).
Propagation delay remains constant under fixed conditions because physical distances do not change. For example, if a signal travels over a fiber optic cable at two-thirds the speed of light, and the distance is 150,000 kilometers, the propagation delay would roughly be \[ \text{Propagation Delay} = \frac{150,000,000}{\left(\frac{3 \times 10^8}{3} \right)} \approx 750 \text{ milliseconds} \]. This constancy helps in predicting end-to-end delay with accuracy for fixed paths.
Calculating End-to-End Delay
End-to-end delay encompasses all four delay components: processing, queuing, transmission, and propagation. It measures the total time a packet takes to travel from the sender to the receiver across a network path. Understanding each component helps in diagnosing network issues and improving network performance. To calculate it, you sum up the four types of delays:
  • Processing Delay
  • Queuing Delay
  • Transmission Delay
  • Propagation Delay
Considering the constants and variables, you might notice that network congestion, reflected in variable queuing delay, tends to complicate predictions. In contrast, knowing constant delays allows for more accurate estimations of packet travel time under normal conditions.

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Most popular questions from this chapter

This elementary problem begins to explore propagation delay and transmission delay, two central concepts in data networking. Consider two hosts, A and B, connected by a single link of rate \(R\) bps. Suppose that the two hosts are separated by \(m\) meters, and suppose the propagation speed along the link is \(s\) meters/sec. Host A is to send a packet of size \(L\) bits to Host B. a. Express the propagation delay, \(d_{\text {prop }}\), in terms of \(m\) and \(s\). b. Determine the transmission time of the packet, \(d_{\text {trans }}\), in terms of \(L\) and \(R\). c. Ignoring processing and queuing delays, obtain an expression for the endto- end delay. d. Suppose Host A begins to transmit the packet at time \(t=0\). At time \(t=d_{\text {trans }}\). where is the last bit of the packet? e. Suppose \(d_{\text {prop }}\) is greater than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? f. Suppose \(d_{\text {prop }}\) is less than \(d_{\text {trans }} .\) At time \(t=d_{\text {trans }}\), where is the first bit of the packet? g. Suppose \(s=2.5 \cdot 10^{8}, L=120\) bits, and \(R=56 \mathrm{kbps}\). Find the distance \(m\) so that \(d_{\text {prop }}\) equals \(d_{\text {trans }}^{-}\)

Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates \(R_{1}=500 \mathrm{kbps}, R_{2}=2 \mathrm{Mbps}\), and \(R_{3}=1 \mathrm{Mbps}\). a. Assuming no other traffic in the network, what is the throughput for the file transfer? b. Suppose the file is 4 million bytes. Dividing the file size by the throughput, roughly how long will it take to transfer the file to Host B? c. Repeat (a) and (b), but now with \(R_{2}\) reduced to \(100 \mathrm{kbps}\).

What advantage does a circuit-switched network have over a packet-switched network? What advantages does TDM have over FDM in a circuit-switched network?

In this problem, we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts analog voice to a digital \(64 \mathrm{kbps}\) bit stream on the fly. Host A then groups the bits into 56 -byte packets. There is one link between Hosts A and B; its transmission rate is 2 Mbps and its propagation delay is \(10 \mathrm{msec}\). As soon as Host A gathers a packet, it sends it to Host B. As soon as Host B receives an entire packet, it converts the packet's bits to an analog signal. How much time elapses from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B)?

Consider Figure \(1.19\) (b). Now suppose that there are \(M\) paths between the server and the client. No two paths share any link. Path \(k(k=1, \ldots, M)\) consists of \(N\) links with transmission rates \(R_{I}^{k}, R_{2}^{k}, \ldots, R_{N}^{k}\). If the server can only use one path to send data to the client, what is the maximum throughput that the server can achieve? If the server can use all \(M\) paths to send data, what is the maximum throughput that the server can achieve?

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