Chapter 14: Problem 10
What is the output of the following C++ code? int *p; int *q; p = new int; q = new int; *p = 27; *q = 35; cout << *p << " " << *q << endl; q = p; *q = 73; cout << *p << " " << *q << endl; p = new int; *p = 36; *q = 42; cout << *p << " " << *q << endl;
Short Answer
Expert verified
Outputs: '27 35', '73 73', '36 42'. Likely undefined due to memory handling.
Step by step solution
01
Variable Initialization
The code begins by declaring two pointer variables, `int *p;` and `int *q;`. At this point, they are uninitialized and contain garbage memory addresses.
02
Memory Allocation
The pointers are then set to point to new integer memory locations with `p = new int;` and `q = new int;`. This allocates memory in the heap for each pointer.
03
Assigning Values to Pointers
The values `27` and `35` are assigned to the locations pointed to by `p` and `q` respectively, using the statements `*p = 27;` and `*q = 35;`.
04
First Output
The first output `cout << *p << " " << *q << endl;` prints the values stored at the locations pointed by `p` and `q`, which are `27` and `35`, respectively.
05
Pointer Reassignment
The line `q = p;` makes `q` point to the same memory location as `p`, thus making it lose its original reference, which creates a memory leak for the previous `new int` assigned to `q`.
06
Modify Shared Memory
After `q = p;`, both `*p` and `*q` refer to the same memory location. The value `73` is assigned with `*q = 73;`, which changes the value at this memory location from `27` to `73`.
07
Second Output
The second output `cout << *p << " " << *q << endl;` will display `73` `73` since both pointers point to the same memory location now containing `73`.
08
New Memory Allocation for p
The statement `p = new int;` allocates a new memory location for `p`, leaving the previous memory block containing `73` still pointed to by `q`. The original `73` value now remains unchanged.
09
Assign New Values
The value `36` is assigned with `*p = 36;`, and `42` is attempted on `*q` (which still points to the last shared location). `*q` therefore now attempts to update to `42`, but it affects original value space before reallocation.
10
Third Output
The last line `cout << *p << " " << *q << endl;` prints `36` and the result of the `42` assignment could cause undefined behavior since we altered a previously moved allocation but `q` targeted there.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pointer Variables
In C++, pointer variables are a powerful feature that allow you to handle memory addresses directly. A pointer variable is declared using an asterisk (*) before the variable name, like `int *p;`. This tells the compiler that `p` is a variable that will hold the address of an `int` type data.
When you declare a pointer, it doesn't automatically point to a valid memory address. Initially, it may contain a garbage address unless it is explicitly initialized to point to a specific location.
Here are some key considerations when using pointers:
When you declare a pointer, it doesn't automatically point to a valid memory address. Initially, it may contain a garbage address unless it is explicitly initialized to point to a specific location.
Here are some key considerations when using pointers:
- Always initialize pointers to prevent them from pointing to unintended memory addresses.
- Use the `&` operator to get the address of a variable, which can then be assigned to a pointer.
- Access or modify the value at the pointed address using the dereference operator `*`.
Memory Allocation
Memory allocation in C++ is about reserving memory space in either the stack or the heap. Dynamic memory allocation is done using the `new` operator, which allows you to allocate memory at runtime.
For example, `p = new int;` allocates memory dynamically and assigns the address of that memory to `p`. This means `p` now holds the address of a dynamically created integer.
Important points to remember about dynamic memory:
For example, `p = new int;` allocates memory dynamically and assigns the address of that memory to `p`. This means `p` now holds the address of a dynamically created integer.
Important points to remember about dynamic memory:
- Always pair every `new` with a corresponding `delete` to release memory and avoid memory leaks.
- Dynamic allocation provides more flexibility than static memory allocation.
- Heap memory is limited; watch out for excessive allocations that can exhaust the resources.
Memory Leak
A memory leak occurs when dynamically allocated memory isn't properly freed, thus becoming unreachable. In the example, when `q = p;` is executed, the originally allocated memory for `q` is lost because `q` reassigns to point to what `p` is pointing to.
To prevent memory leaks, follow these best practices:
To prevent memory leaks, follow these best practices:
- Always use `delete` or `delete[]` for every `new` or `new[]` you use to allocate memory.
- Before reassignment of pointers, ensure any dynamically allocated memory is properly deallocated.
- Consider using smart pointers, like `std::unique_ptr` or `std::shared_ptr`, which automatically manage memory and reduce the risk of leaks.
- Tools and features such as sanitizers and static analysis can help identify leaks during testing phases.
Pointer Reassignment
Pointer reassignment changes where a pointer is pointing. When you use `q = p;`, you make `q` point to the same memory location as `p`. After reassignment, both `p` and `q` will refer to the same memory.
This can be a useful technique but requires caution:
This can be a useful technique but requires caution:
- Be aware of what the original pointer (`q` in this case) was pointing to, as it's easy to accidentally create a memory leak if you overwrite the address without first freeing it.
- Remember that changing the value at the shared memory location will affect all pointers referring to that memory. Always trace all pointers involved.
- Reassignment does not free the original memory, so ensure proper memory management after such operations.