/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Find the point on \(2 x+3 y+z-11... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the point on \(2 x+3 y+z-11=0\) for which \(4 x^{2}+y^{2}+z^{2}\) is a minimum.

Short Answer

Expert verified
\(\left(\frac{1}{2}, 3, 1\right)\)

Step by step solution

01

State the problem

Identify the condition given by the equation of the plane and the function to minimize.Given: Plane equation, \(2x + 3y + z - 11 = 0\).Function to minimize: \(4x^2 + y^2 + z^2\).
02

Setup Lagrange Multipliers

Use the method of Lagrange multipliers to find the minimum.Define the Lagrangian as:\[ \textbf{L}(x, y, z, \lambda) = 4x^2 + y^2 + z^2 + \lambda (2x + 3y + z - 11) \]
03

Compute the Partial Derivatives

Compute the partial derivatives of \textbf{L} with respect to x, y, z, and \lambda, and set them to zero.\[\frac{\partial \textbf{L}}{\partial x} = 8x + 2\lambda = 0 \frac{\partial \textbf{L}}{\partial y} = 2y + 3\lambda = 0 \frac{\partial \textbf{L}}{\partial z} = 2z + \lambda = 0 \frac{\partial \textbf{L}}{\partial \lambda} = 2x + 3y + z - 11 = 0 \]
04

Solve the partial derivatives

Solve the system of equations to find x, y, z, and \lambda.From \(\frac{\partial \textbf{L}}{\partial x} = 0\):\[ 8x + 2\lambda = 0 \ 4x + \lambda = 0 \ \lambda = -4x \]From \(\frac{\partial \textbf{L}}{\partial y} =0\):\[ 2y + 3\lambda = 0 \ 2y - 12x = 0 \ y = 6x \]From \(\frac{\partial \textbf{L}}{\partial z} = 0\):\[ 2z + \lambda = 0 \ 2z - 4x = 0 \ z = 2x \]
05

Substitute back into the constraint

Substitute the expressions for y and z back into the plane's equation to find x.\[ 2x + 3(6x) + (2x) - 11 = 0 \ 2x + 18x + 2x - 11 = 0 \ 22x - 11 = 0 \ 22x = 11 \ x = \frac{11}{22} = \frac{1}{2} \]
06

Find corresponding y and z values

Using x = \frac{1}{2}, solve for y and z.\[ y = 6x = 6(\frac{1}{2}) = 3 \ z = 2x = 2(\frac{1}{2}) = 1 \]
07

Conclusion

The point on the plane that minimizes the function is.\(\left(\frac{1}{2}, 3, 1\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Optimization
Optimization is a fundamental concept in mathematics where we aim to find the best solution, often the maximum or minimum, within a given set of constraints. In this exercise, we are looking for the point on the plane defined by the equation \(2x+3y+z-11=0\) that minimizes the function \(4x^2+y^2+z^2\). This means finding a set of values for \(x, y,\) and \(z\) that satisfies the plane's equation while keeping the value of our function as low as possible. By achieving this, we solve for the most 'optimal' point that meets all the conditions. This technique is crucial in numerous real-world applications like engineering and economics, where optimal resource allocation is necessary.
Multivariable Calculus
Multivariable calculus extends single-variable calculus techniques to functions with several variables. In this context, we deal with functions of the form \(f(x, y, z)\), where changes in one variable can affect the output in conjunction with changes in others. The given function \(4x^2+y^2+z^2\) is a classic example, where each variable influences the overall value of the function. Multivariable calculus allows us to understand and manipulate these functions to explore surfaces and curves in higher dimensions, solve equations, and find optimal points as we did in this exercise. Partial derivatives play a crucial role here, as they help us determine the rate of change of the function concerning each of its variables.
Constrained Minimization Techniques
Constrained minimization involves finding the minimum value of a function subject to certain constraints. In our exercise, this means minimizing \(4x^2+y^2+z^2\) while still satisfying the plane equation \(2x+3y+z-11=0\). The Lagrange multipliers method is an effective technique to handle such problems. By introducing a new variable \(\lambda\) (called the Lagrange multiplier), we create the Lagrangian function, which helps us convert the constrained problem into an unconstrained one. We then differentiate this Lagrangian with respect to all variables (including \(\lambda\)) and solve the resulting system of equations. This method provides the optimal values and ensures that our solution respects the given constraint.
Partial Derivatives
Partial derivatives measure how a multivariable function changes when one of its variables is varied while the others are held constant. They are essential in optimization problems with multiple variables. For our problem, we compute the partial derivatives of the Lagrangian \(\mathbf{L}(x, y, z, \lambda) = 4x^2 + y^2 + z^2 + \lambda (2x + 3y + z - 11)\) with respect to \(x, y, z,\) and \(\lambda\). Setting these partial derivatives to zero gives us a system of equations, which we solve to find our variables' optimal values. This systematic approach enables us to dissect complex multivariable relationships and optimize functions within constraints.

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Most popular questions from this chapter

The formulas of this problem are useful in thermodynamics. (a) Given \(f(x, y, z)=0,\) find formulas for $$\left(\frac{\partial y}{\partial x}\right)_{z}, \quad\left(\frac{\partial x}{\partial y}\right)_{z}, \quad\left(\frac{\partial y}{\partial z}\right)_{x}, \quad \text { and } \quad\left(\frac{\partial z}{\partial x}\right)_{y}$$ (b) Show that \(\left(\frac{\partial x}{\partial y}\right)_{z}\left(\frac{\partial y}{\partial x}\right)_{z}=1\) and \(\left(\frac{\partial x}{\partial y}\right)_{z}\left(\frac{\partial y}{\partial z}\right)_{z}\left(\frac{\partial z}{\partial x}\right)_{y}=-1\) $$\begin{aligned}&\text { (c) If } x, y, z \text { are each functions of } t, \text { show that }\left(\frac{\partial y}{\partial z}\right)_{x}=\left(\frac{\partial y}{\partial t}\right)_{x} /\left(\frac{\partial z}{\partial t}\right)_{x} \text { and }\\\ &\text { corresponding formulas for }\left(\frac{\partial z}{\partial x}\right)_{y} \text { and }\left(\frac{\partial x}{\partial y}\right)_{z} \end{aligned}$$

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